Find the charge and the stored energy for this situation

Question

A charged capacitor stores energy defined by the equation:

E=1/2 CV^2 = 1/2 QV

where C is the capactance, V is the voltage, and Q is the charge. The capactiance of a variable capaciyor can be charged from 60 pF to 960 pF by turning the dial from 0' to 180'. With the dial set at 180', the capacitor is connected with a 450 V source. Find the charge and the stored energy for this situation.

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