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◦ You are 60 years old. Currently, you have $
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<p>So:</p> <p>(XX,XXX)(X.XX)<sup>y</sup>= XX,XXXX</p> <p>y = 10.X</p> <p>Hence it XXXX take XX approximately<strong>XX.5 XXXXX, or XX years and X months</strong>, XX XXXXXXX our XXXXX.</p> <p><br>c) XX your XXXXX continue XX earn X XXXXXXX annually XXX your XXXX expectancy XX XX XXXXX, XXXX XX XXX XXXXXXX you XXX XXXXXXXX each XXXX?</p> <p>Taking that XXXX XXXXXXXX</p> <p>(XX,XXX)(X.09)<XXX>y</sup>= 17,000y</p> <p>But XXXXXXXX y with "XX" XXX XXX solving XXX XXX XXXXX XX $XX,XXX:</p> <p>(60,XXX)(X.XX^XX) = 18x</p> <p>x = XXX XXX.225 / XX =<strong>$ 15,XXX.73 per year</strong></p> <p><strong>I XXXX XXXX you found this XXXXXX useful XXXXXXX your XXXXXXX. XX XXXX a considerable amount of thought, XXXX, XXX XXXXXX XX XXXXXXX, XXX XXX I'XXXXXXXXXX appreciate a XXXXXXXXX rating! XX XXXXX XXXXXX make my day! :)</XXXXXX></p>">
