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◦ You are 60 years old. Currently, you have $
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<p>XX:</p> <p>(XX,XXX)(X.09)<XXX>y</sup>= 17,000y</p> <p>y = XX.5</p> <p>Hence it will take us XXXXXXXXXXXXX<strong>10.X years, or 10 years and 6 months</strong>, XX exhaust our funds.</p> <p><XX>c) XX XXXX XXXXX XXXXXXXX XX earn X percent XXXXXXXX XXX XXXX XXXX expectancy XX XX XXXXX, what XX XXX maximum you XXX XXXXXXXX XXXX XXXX?</p> <p>Taking XXXX XXXX equation</p> <p>(60,XXX)(1.09)<sup>y</XXX>= 17,000y</p> <p>But swapping y with "XX" and now solving for the place of $17,000:</p> <p>(60,000)(X.XX^XX) = XXX</p> <p>x = XXX XXX.XXX / XX =<XXXXXX>$ XX,723.73 XXX XXXX</strong></p> <p><XXXXXX>I hope that you XXXXX this XXXXXX useful towards XXXX studies. XX XXXX a XXXXXXXXXXXX amount XX thought, time, XXX XXXXXX XX XXXXXXX, XXX XXX I'XXXXXXXXXX appreciate a XXXXXXXXX rating! XX XXXXX XXXXXX make my XXX! :)</XXXXXX></p>">
