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A tank has two identical orifices, each 5 cm in
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</figure> <p>Once the liquid passes the vena XXXXXXXXX, XXX air XXXXX XXX liquid down due XX friction and the XXXX XXXXXXXX.</p> <p>XXX, XX XXXX XXX things to consider XXXX XXXX.</p> <p>The XXXXX XX XXX XXXXXXXXX XXXXXXXX XXX the XXXXXX XX XXX XXXX of the vena XXXXXXXXX XX determine XXX rate XX XXXXXXXXX, X.</p> <p>Discharge velocity:<br></p> <p>XX we know XXXX the XXXXXXXXXXX velocity of XXX flow XXX XX XXXXXXXXXX XXXXX the equationV<XXX>i</XXX>= √XXX.<XX></p> <p>XXXX, XX upper orifice,XX = root(X*X.8*X) = 8.XX m/s<br>At XXXXX orifice, Vi = XXXX(X*X.X*6) = XX.84 m/s</p> <p>Discharge XXXXXXXX, X = XX* coefficient of viscocity<XX>XXX upper XXXXXXX, XX=X.85*X.XX = 8.673 m/s<XX>XXX lower XXXXXXX, XX= XX.XX*0.98 = 10.XX m/s</p> <p>Secondly, the area XX the XXXX contracta, A = Ao*coefficient XX contraction (Ao = Area of XXXXX section of the orifice)<br>XXXXXXXXX, X = pie*(r^X)*X.64<br>XXX upper orifice, X = (XX/X)*(X/2)^2*X.XX = 12.XX XXX or X.XXXXXX m2<br>XXX XXXXX XXXXXXX, X =(22/X)*(X/X)^2*0.64 =XX.57 XXX or 0.001257 XX</p> <p>XXXXX )Now, XXX discharge or flow, X XXXX an XXXXXXX = V*A = XX*Cv*XX*XX (XX = Contraction XXXXXXXXXXX, XX= XXXXXXXXXXX XX viscosity)<br>For XXXXX orifice, XX= Vu*X = 8.673*0.001257 = X.XXXX m3/s<br>For lower orifice, XX = XX*X = 10.XX*0.XXXXXX = X.0133 XX/s</p> <p>XXXX X)</p> <p>XXXXXXXXXX XXXXXXXX XX XXXXX XXXXXXX, XX = 8.XXX m/s<XX>XXXXXXXXXX velocity of lower orifice, XX = XX.62 m/s</p> <p>Let the XXXXXXXXXX XXXXXXXX at which, the XXXXX XXXXXXXXX XX X.</p> <p>XXXXXXXXX, X= X*t (X= velocity XX the flow, t = time) or t = X / V<XX>XXXXX equation XX XXX XXXXXXXXXXX motion,<br>y = ut + X/2 g*t^X</p> <p>But, u = 0, therefore, y = 1/X*g*t^X</p> <p>XXX, XXX XXXXX orficie at any point of XXXX XXXXXXXX distance travelled by XXXX, Yu= 1/X*g*(X/Vu)^X<XX> For XXXXX orifice at any XXXXX of time XXXXXXXX distance XXXXXXXXX XX flow, XX = 1/2*g*(X/XX)^X</p> <p>XXXXXXXX XXXXXXX, X^X = 2*XX*Vu^X/g - Eqn X<XX>For lower orifice, X^2 = X*XX*Vl^X/g - XXX X</p> <p>XXXXX X XX XXXX XX XXX point of XXXXXXXXXXXX, XXXXXXXXX, XXXXXXXX eqn 1 XXX eqn 2 we XXX,</p> <p>Vu^X*Yu = Vl^X*Yl - XXX 3</p> <p>Now XX the XXXXX of intersection XX = Yl+X - Eqn X(as one is XX a depth of X m XXX XXXXXXX at depth of 6 m)<XX><XX>Putting XXX X in XXX 3 XX get,</p> <p>Vu^X*(XX+2) = XX^X*YI</p> <p>XXXXXXX the XXXXXX of Vu and XX in XXX equation we XXX,</p> <p>8.673^X*(YI+X) = 10.XX^X*XX<br>Or, XX.XX*(YI+X) = 112.XX*YI<br>Or, XX.XX XX= 150.44<br>XX, XX = 4 m</p> <p>Therefore, XXX distance of intersection XXXX the XXXXX orifice is XX , upper orifice is 6 m and XXXXXXX XX XXX water is XX m.</p> <p><br></p>">
