And probability of any event is 1 - (probability of XXXXXXXX XXXXXXXXX)
P(A)= 1 - P(A')
A' XX XX one having XXXXX XXXX XXXX. If XX find X(X') , we can find X(A).
Now X' XX XXX XXXXX thatno one having XXXXX XXXX XXXX is XXX XXXXXXXX.
XX XXXX 165442 people and each XXXXXX can have XX maximum159807 XXXXX. Now let XXXX XXX XXXXXX XX XX, XX, P3.....P165441, XXXXXXX.
XX people XXX have any XXXXXX XX XXXXX out XX [X,2,3,4.......XXXXXX,XXXXXX,159807] XXXXX. XX, XXXXX are XXXXXXXXXXXX XXXX XXXXXXX.
P1 has XXXXX
P2 XXX 2hairs
P3 has XXXXXX
...................
P159807has XXXXXX hairs......
XXX XXXXX XXXX
XXXXXXXXXX not have 159808 hairs so he can XXXX XXX XXXXXX XXXXXXX (1,X....159807) XXX XXXXX his number would match XX XXX hairs XXXXX XX XXX XXXXXXXX one.
Hence its XXXXXXXXXX XX not have same hairs after 159807 XXXXXX. So its XXXXXXXXXX for X' to happen. XXX XXXXXXXXXXX XX an XXXXXXXXXX event XX X.
XXXXX X(X') = 0
X(X) = X-P(A') =X-X = 1
Probabilitythat at XXXXX XXX XXXXXX XXXX exactly XXX XXXX XXXXXX XX XXXXX on XXXXX XXXXX.