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Honors Precalculus Limits problem
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</XXXXXX> <p>f(x)=(x^2-5*x+X)/(x^X-1)</p> <p>If you XXXXXXXXX XXXX solution, what you XXXX XXX is:</p> <p>f(x)=(x-X)(x-4)/(x-1)(x+1)</p> <p>XX you can XXX in the XXXXX also that the XXXXX XX XXXXXXXXXXX at x= -X</p> <p>1. XXXXX XXX XXXXX XX XXX XXXXXXXX XXX:<br>Domain:<XX>x E (-XXXXXXXX, + XXXXXXXX) - {-1}</p> <p>Range:</p> <p>y X (-XXXXXXXX, infinity) - {X}</p> <p>XXXXX XXXXXXXXXX XXXXXXXX XX x= -X<br><XX></p> <p>2. XXX XXXX XX shown in XXX XXXXX attached as a XXX file.</p> <p>As already XXXXX out in question X the XXXXXXXXXX function XX the XXXXXXXX XX f(x)=(x-4)/(x+X)<br>The XXXX XX the XXXXXXXX is x = X which XXX XX XXXX in XXX XXXXX.<br>XX x -> infinity,</p> <p>Lim (x-X)/(x+X) = XXX (X-4/x)/(1+X/x)<XX>x-&XX;XXXXXXXX x-&XX;XXXXXXXX</p> <p>As XX know XXX number when XXXXXXX XX XXXXXXXX XXXXXX to zero (n/XXXXXXXX=0)</p> <p>XXXXXXXXX, the value XX the equation when x approaches XXXXXXXX XX X.</p> <p>XXX, if XX XXXX the XXXX changes XX a XXXX XXXX XX XXX,<br><XX> + - +<br><------------------|--------------------------------|--------------------------------&XX;<br>-XXXXXXXX -X X +infinity</p> <p><XX></p> <p>The sign XXXXXXX XXXXXXX XX XXXX x=4 and x=-1. At x->-X XXX denominator approaches X XXXXXXXXX the XXXXXXXX is asymphtotic as x-&XX;-X.</p> <p>X. XX x-&XX; -X, the XXXXXXXXXXX XX the simplified XXXXXXXX, f(x) = (x-X)/(x+X) approaches 0. XXXXXXXXX, XXX equation XXXXXXXXXX XXXXXXXX.</p> <p><br>X. At x=X the value of XXX XXXXXXXXX = X while XXXXXXXXXXX is X.<br>y= X XX x=4.<br>XX XXX XXXXXXX of XXXXX, XXXX x-&XX;4 from either XXXXXXXXX XXX XXXXX remains X XXX XX XXXXXXXXX XXXXXXXXXX.<br>XXXX can also be verified by looking XX XXX XXXXX.<br>XXX XXXX XX continuous XX x=4. But, it XX not continuous at x=-X.</p>">
