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Phase 1:A bus starts from rest at point A and accelerates at the rate of 0.8 m/s^2 unit it reaches a speed of 12 m/s.</strong></p> <p>v = u + at </p> <p>12 = 0 +(0.8*t)</p> <p>Time taken to accelerate,t= XX/(X.8) = XX XXXXXXX <XXXXXX XXXXX="redactor-inline-converted">[t1 = 15 seconds]</XXXXXX></p> <p>XXXXXXXX traveled while accelerating to 12 m/s, s = ut + (X/X)*a*(t^X)</p> <p>s = (0*t) + X.X* 0.8 *(XX*XX) = 90 m</p><p><br></p><p><XXXXXX XXXXX="redactor-XXXXXX-converted">Phase 2:XXXXXX proceeds XX 12 m/s XXXXX XXX breaks are applied; it XXXXX XX XXXX XX XXXXX B, 42 m XXXXXX XXX XXXXX XXXXX the XXXXXX XXXX XXXXXXX</strong><br></p><p>Total XXXXXXXX = 300 m</p><p>Initial XXXXXXXX XXXXXXX while accelerating = XX m</p><p>Distance covered while de-accelerating = 42 m</p><p>XXXX, distance covered XX 12 m/s uniform XXXXX =XXX - (XX+XX) = 300 - 132 = 168 m</p><p>XXXX XXXXX XX XXXXX XXX m,</p><p>t = XXXXXXXX covered / uniform speed = XXX / XX =XX XXXXXXX <strong class="XXXXXXXX-XXXXXX-XXXXXXXXX">[t2 = XX XXXXXXX]</XXXXXX></p><p><XXXXXX class="redactor-inline-converted"><br></strong></p><p>XXXX 12 m/s, it XXXXX XX rest (XXXXX XXXXX = X)</p><p>v = u +XX</p><p>X = 12 +XX</p><p>XX, at = -12</p><p><br></p><p>XXXXXXXX XX de-accelerate = XX m</p><p>XXXXX, s = ut + (X/X)*a*(t^X)</p><p>XX = (12*t)+(1/2)*a*(t^t)</p><p>42 = t *(XX +(1/2)* a* t)</p><p>Use XXXXX XX = -XX</p><p>42 = t * (XX - X )</p><p>t = X seconds <XXXXXX XXXXX="redactor-XXXXXX-XXXXXXXXX">[XX = X seconds]</XXXXXX></p><p><strong>XXXXX time = t1 + t2 +t3 = XX + 14 +X = XX XXXXXXX</strong></p> <p><br></p> <p><XX></p>">
