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Phase 1:A bus starts from rest at point A and accelerates at the rate of 0.8 m/s^2 unit it reaches a speed of 12 m/s.</strong></p> <p>v = u + at </p> <p>12 = 0 +(0.8*t)</p> <p>Time taken to accelerate,t= 12/(X.X) = XX seconds <XXXXXX XXXXX="redactor-inline-XXXXXXXXX">[XX = XX XXXXXXX]</strong></p> <p>Distance traveled XXXXX XXXXXXXXXXXX XX XX m/s, s = ut + (1/X)*a*(t^X)</p> <p>s = (X*t) + X.5* X.8 *(15*15) = 90 m</p><p><br></p><p><XXXXXX XXXXX="XXXXXXXX-XXXXXX-converted">Phase 2:XXXXXX XXXXXXXX XX 12 m/s XXXXX XXX breaks are applied; it comes to XXXX at XXXXX B, XX m XXXXXX the XXXXX where the breaks XXXX XXXXXXX</XXXXXX><XX></p><p>XXXXX XXXXXXXX = 300 m</p><p>XXXXXXX distance XXXXXXX while XXXXXXXXXXXX = 90 m</p><p>Distance XXXXXXX XXXXX de-XXXXXXXXXXXX = XX m</p><p>XXXX, distance XXXXXXX at 12 m/s uniform speed =300 - (90+XX) = XXX - XXX = XXX m</p><p>Time taken XX XXXXX XXX m,</p><p>t = distance covered / XXXXXXX XXXXX = 168 / XX =14 XXXXXXX <strong XXXXX="redactor-XXXXXX-converted">[t2 = XX seconds]</XXXXXX></p><p><strong class="XXXXXXXX-XXXXXX-converted"><XX></XXXXXX></p><p>From XX m/s, it comes to XXXX (final speed = X)</p><p>v = u +XX</p><p>0 = 12 +XX</p><p>So, at = -12</p><p><XX></p><p>Distance XX de-accelerate = XX m</p><p>Using, s = ut + (X/2)*a*(t^X)</p><p>XX = (XX*t)+(1/X)*a*(t^t)</p><p>42 = t *(XX +(X/2)* a* t)</p><p>XXX XXXXX XX = -XX</p><p>XX = t * (XX - 6 )</p><p>t = X seconds <XXXXXX XXXXX="redactor-inline-XXXXXXXXX">[XX = 7 XXXXXXX]</XXXXXX></p><p><XXXXXX>Total time = t1 + XX +XX = XX + 14 +7 = XX XXXXXXX</XXXXXX></p> <p><br></p> <p><XX></p>">
