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Phase 1:A bus starts from rest at point A and accelerates at the rate of 0.8 m/s^2 unit it reaches a speed of 12 m/s.</strong></p> <p>v = u + at </p> <p>12 = 0 +(0.8*t)</p> <p>Time taken to accelerate,t= 12/(X.8) = 15 seconds <XXXXXX class="redactor-XXXXXX-XXXXXXXXX">[XX = 15 seconds]</strong></p> <p>Distance XXXXXXXX XXXXX XXXXXXXXXXXX XX 12 m/s, s = ut + (X/X)*a*(t^2)</p> <p>s = (X*t) + 0.5* X.8 *(XX*15) = 90 m</p><p><br></p><p><XXXXXX class="XXXXXXXX-inline-XXXXXXXXX">XXXXX X:Itthen XXXXXXXX XX XX m/s XXXXX XXX breaks are applied; it comes XX XXXX XX XXXXX X, 42 m beyond XXX XXXXX where XXX XXXXXX were applied</strong><br></p><p>XXXXX XXXXXXXX = 300 m</p><p>XXXXXXX distance covered while XXXXXXXXXXXX = 90 m</p><p>Distance XXXXXXX XXXXX de-accelerating = 42 m</p><p>Thus, XXXXXXXX XXXXXXX XX 12 m/s XXXXXXX XXXXX =300 - (XX+42) = 300 - XXX = XXX m</p><p>XXXX taken XX cover XXX m,</p><p>t = XXXXXXXX XXXXXXX / uniform speed = XXX / XX =14 XXXXXXX <strong class="redactor-inline-converted">[t2 = XX seconds]</strong></p><p><XXXXXX XXXXX="redactor-inline-converted"><br></XXXXXX></p><p>XXXX XX m/s, it XXXXX to XXXX (final XXXXX = X)</p><p>v = u +XX</p><p>0 = 12 +XX</p><p>So, XX = -XX</p><p><XX></p><p>Distance XX de-XXXXXXXXXX = XX m</p><p>Using, s = ut + (X/X)*a*(t^X)</p><p>XX = (XX*t)+(1/2)*a*(t^t)</p><p>XX = t *(12 +(X/X)* a* t)</p><p>XXX XXXXX XX = -XX</p><p>42 = t * (12 - X )</p><p>t = 7 seconds <XXXXXX class="redactor-XXXXXX-converted">[t3 = X XXXXXXX]</strong></p><p><strong>Total time = t1 + t2 +t3 = XX + XX +7 = XX seconds</XXXXXX></p> <p><XX></p> <p><br></p>">
