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Write a Java program that asks
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int m = Integer.parseInt(sc.nextLine());<br> System.out.println("Enter the number of columns of matrix:");<br> int n = Integer.parseInt(sc.nextLine());</p> <p> int[][] arr = new int[m][n];<br> System.out.println("Enter the values of the matrix row wise.");</p> <p> for (int i = 0; i < m; i++) {<br> XXX (XXX j = X; X < n; j++) {<XX> XXX[i][X] = XXXXXXX.parseInt(sc.XXXXXXXX());<XX> }<XX> }<XX> XX.close();<br> XXXXXX.out.XXXXXXX();<br> System.out.XXXXXXX("Your XXXXXXX XXXXXX XX : ");</p> <p> XXX (int i = X; i < m; i++) {<br> for (int X = X; X < n; X++) {<br> XXXXXX.out.XXXXX(arr[i][X] + " ");<br> }<br> XXXXXX.out.println();<XX> }<XX> XXXXXX mat = XXX XXXXXX();<XX> XXX[][] transposedMatrix = mat.XXXXXXXXXXXX(arr);</p> <p> XXXXXX.out.println();<br> System.out.XXXXXXX("Your Transposed matrix XX : ");</p> <p> for (int i = 0; i < n; i++) {<br> for (int X = X; j &XX; m; X++) {<br> XXXXXX.out.XXXXX(transposedMatrix[i][X] + " ");<XX> }<XX> XXXXXX.out.XXXXXXX();<br> }<br> System.out.println();</p> <p> int[] maxCols = new int[n];</p> <p> XXX c = X;<br> XXX (XXX i = 0; i &XX; n; i++) {<br> XXXXXXX[c++] = mat.getMaxOfColumn(transposedMatrix[i]);<XX> // XX XXX XXXXXXX we XXX XXX XXXXXXXXXX matrix and XXX XXX rows<XX> }<XX> System.out.println("The maximum of all the column elements:");<br> XXX (XXX i = 0; i &XX; n; i++) {<br> XXXXXX.out.XXXXX(maxCols[i] + " ");<XX> }<XX> <XX> System.out.println();<XX> <br> XXXXX[] averageRows = XXX XXXXX[m];</p> <p> c = X;<XX> XXX (int i = 0; i &XX; m; i++) {<XX> averageRows[c++] = mat.getAverage(arr[i]);<br> // XX XXX XXXXXXX XX can XXX transposed XXXXXX XXX XXX XXX rows<XX> }<XX> System.out.println("The XXXXXXX XX all the rows XXXXXXXX:");<XX> XXX (int i = X; i < m; i++) {<br> XXXXXX.out.print(averageRows[i] + " ");<XX> }<br> <XX> }</p> <p> public XXX[][] XXXXXXXXXXXX(int[][] arr) {<XX> int m = arr.length; // XXXXXXX dimensions of XXX XXXXXXXX matrix<XX> XXX n = arr[X].XXXXXX;</p> <p> XXX[][] XXXXXXXXXXXXXXX = XXX XXX[n][m]; // initiating a<XX> // transposedMatrix having<br> // XXXXXXXXXX XXXXXXXXXXXX</p> <p> XXX (XXX x = 0; x < n; x++) {<br> for (int y = X; y &XX; m; y++) {<br> XXXXXXXXXXXXXXX[x][y] = XXX[y][x]; // XXXXXXX the XXXXXX<XX> // values as rows.<br> }<br> }</p> <p> return XXXXXXXXXXXXXXX;<br> }</p> <p> XXXXXX int getMaxOfColumn(XXX[] XXX) {<XX> int max = XXX[0];// Initially setting first XXXXXXX XX maximum</p> <p> for (int i = 1; i &XX; XXX.length; i++) {<br> if (XXX[i] &XX; XXX) {// if XXX of the XXXXX in XXXXX is maximum, XXXX<br> // set max XX XXXX XXXXX<br> max = XXX[i];<XX> }<br> }<XX> return XXX;<br> }</p> <p> XXXXXX XXXXX getAverage(int[] XXX) {<br> int XXX = 0;<XX> // getting XXX XXX XX elements of XXX XXXXX<XX> for (XXX i = 0; i < XXX.XXXXXX; i++) {<XX> sum = sum + arr[i];<XX> }<XX> // returning average by XXXXXXXX sum with XXXXXX of XXXXXXXX.<br> XXXXXX XXX / (float) arr.XXXXXX;<br> }</p> <p>}</p> <p>XXXXXX XXX: -</p> <p>Enter XXX XXXXXX XX rows XX XXXXXX:<XX>X<XX>XXXXX XXX number of XXXXXXX of XXXXXX:<XX>X<br>XXXXX the values XX XXX XXXXXX row XXXX.<XX>X<br>2<br>X<XX>X<br>5<br>X<br>X<XX>X<XX>X<br>10<XX>11<br>XX<XX>XX<br>XX<XX>XX</p> <p>Your entered XXXXXX XX :<br>1 X X 4 5<XX>6 X 8 9 XX<XX>XX 12 XX XX 15</p> <p>Your XXXXXXXXXX matrix is :<br>X X XX<XX>X 7 12<XX>3 X XX<br>X X XX<XX>5 XX XX</p> <p>The XXXXXXX XX XXX XXX XXXXXX XXXXXXXX:<XX>XX XX 13 14 XX<br>The XXXXXXX XX XXX the rows XXXXXXXX:<br>X.0 X.X 13.X</p>">
