b. X(X = 5) = b(5, 10, X.X) = = X.1029
c. X(X = 8) = b(X, 10, 0.X) = = 0.XXXXX
X.94 A certain type XX XXXXXX seed germinates 90% of XXX XXXX. X backyard XXXXXX XXXXXXX 25 seeds.
a. What is XXX XXXXXXXXXXX XXXX XXXXXXX XX XXXXXXXXX?
b. What XX the probability XXXX 20 or XXXX XXXXXXXXX?
B(XX, 25, X.9) + b(XX, 25, X.X) + b(22, 25, X.X) + b(XX, XX, 0.X) + b(XX, XX, X.X) + b(25, 25, 0.9) = 0.0645 + 0.XXXX + X.XXXX + X.XXXX + X.199 + X.0717 = 0.XXX
c. What XX XXX probability that 24 or XXXXX XXXXXXXXX?
X-p(XX germinate) = 1-b(25, 25, 0.9) = 1-.0717 = 0.XXX
d. What is XXX expected XXXXXX of seeds XXXX XXXXXXXXX?
We have E(X) = n*p = 25*X.X = XX.5