So you XXX, we get 10^-2 new mol XX H+.
Since XXXXXXX XXXX XXXXXX XXX XXXXXXXXXXX because of XXX new H+ (XXXXXX ion effect), we XXXX to XXX the Henderson Hasselbach XXXXXXXX:
This XX XXX form you XXXX, but we're going XX XXX XXX XXXX XXXXX XXXX XXXXX we XXX't know how many H+ we have in XXX XXXXX XXXXX (XXXX how many we XXX adding). XXX don't XX know? Because, XXXX XXXX with XXX XXXXXXXXXXX XXXXXXXX, if you add a XXXXXXX, the reaction will XXXX towards the XXXXXXXXX. The addition XX H+ XXXXX glycine will take back XXXX XX the X+ it has (XXXXX XX the XX XXXXXX). Here's the "pure"/original from XX the XXXXXXXX XXXXX:
XXX's XXX x in places XXXXX XX XXX XXX disassociation XX glycine. Thankfully, XX XXXX XX, glycine XXXXXXXXXXXXX in a clean 1:X ratio (we XXX XXXXXXXXXX pka XX ka):
Solving XXX x, we XXX 0.02503 (N.B.: you'll XXX XXX XXXXXX, but you XXX't have XXXXXXXX XXXXX). XX're XXX XXXX. This XX how many H+ is XXXXX by XXXXXXX. XX you can see from XXX XXXXXXXX XXXXX, total X+ is x + XX^-X
XX now, final XXXX, we XXXXX for the XXXXXX XX X+:
But don't forget! There's a XXX volume! XX doesn't XXXXXX XXX XXXX, but better XXXX XXXX sorry:
You XXXXXX XXX X.XX as your XXX XX.