So you XXX, we XXX XX^-X new XXX XX X+.
Since XXXXXXX XXXX XXXXXX XXX XXXXXXXXXXX XXXXXXX XX XXX new H+ (common XXX XXXXXX), we need XX XXX XXX XXXXXXXXX Hasselbach equation:
This is XXX form you XXXX, but we're going XX use the more basic form XXXXX XX don't XXXX how many H+ XX have in the first place (XXXX how XXXX we are adding). XXX XXX't we XXXX? Because, just like XXXX XXX XXXXXXXXXXX reaction, if you add a XXXXXXX, XXX XXXXXXXX XXXX XXXX XXXXXXX XXX reactants. The addition XX X+ means glycine will take back XXXX XX the H+ it has (based on the XX XXXXXX). XXXX's XXX "XXXX"/XXXXXXXX from of the XXXXXXXX above:
XXX's XXX x in XXXXXX where XX see XXX XXXXXXXXXXXXXX XX XXXXXXX. Thankfully, XX XXXX pH, XXXXXXX disassociates in a XXXXX 1:X ratio (we are XXXXXXXXXX XXX to ka):
Solving for x, XX get 0.XXXXX (N.B.: you'll XXX XXX values, but you can't XXXX negative XXXXX). XX're not XXXX. This XX how XXXX H+ XX given XX XXXXXXX. As you can see XXXX the XXXXXXXX above, XXXXX X+ is x + XX^-2
XX XXX, XXXXX XXXX, XX solve XXX XXX number XX H+:
XXX don't forget! There's a new volume! XX XXXXX't matter too much, but better XXXX XXXX XXXXX:
You should XXX X.35 XX XXXX new pH.