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Biochemistry PH Problem
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</figure> <figure><img src="https://schoolsolver.s3.amazonaws.com/media/attachments/642CodeCogsEqn1.gif" data-XX="https://schoolsolver.s3.XXXXXXXXX.com/XXXXX/attachments/642CodeCogsEqn1.XXX"></XXXXXX> <XXXXXX><img src="https://schoolsolver.s3.amazonaws.com/XXXXX/XXXXXXXXXXX/080CodeCogsEqn2.gif" data-s3="XXXXX://schoolsolver.XX.XXXXXXXXX.XXX/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXX.gif"></figure> <p>XX you XXX, we XXX 10^-X XXX XXX of X+.</p> <p>Since XXXXXXX XXXX XXXXXX XXX equilibrium XXXXXXX of XXX new H+ (common ion XXXXXX), XX XXXX XX XXX XXX XXXXXXXXX Hasselbach XXXXXXXX:</p> <figure><XXX XXX="XXXXX://schoolsolver.XX.amazonaws.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX.XXX" XXXX-s3="XXXXX://schoolsolver.s3.XXXXXXXXX.com/media/attachments/751MSP11822022gc1a1ih0556200005iii3cd5e647c59i.gif"></XXXXXX> <p>This XX XXX XXXX you know, XXX XX're XXXXX XX use the XXXX basic form since XX XXX't know how many H+ we have in the first XXXXX (XXXX how many XX XXX adding). Why don't we know? Because, XXXX XXXX with any equilibrium reaction, if you add a product, the XXXXXXXX XXXX XXXX towards XXX XXXXXXXXX. XXX addition of H+ means glycine XXXX XXXX XXXX XXXX of XXX H+ it has (XXXXX XX XXX Ka XXXXXX). XXXX's the "XXXX"/XXXXXXXX XXXX of the equation above:</p> <figure><XXX XXX="XXXXX://schoolsolver.s3.XXXXXXXXX.XXX/XXXXX/XXXXXXXXXXX/XXXXXXXXXX.XXX" data-s3="https://XXXXXXXXXXXX.XX.XXXXXXXXX.com/media/XXXXXXXXXXX/XXXXXXXXXX.XXX"></XXXXXX> <p>Let's XXX x in XXXXXX XXXXX XX XXX XXX XXXXXXXXXXXXXX XX XXXXXXX. Thankfully, XX XXXX pH, XXXXXXX XXXXXXXXXXXXX in a XXXXX X:1 ratio (XX are converting pka XX ka):</p> <XXXXXX><img src="https://schoolsolver.s3.amazonaws.com/XXXXX/XXXXXXXXXXX/450CodeCogsEqn3.XXX" XXXX-XX="https://XXXXXXXXXXXX.s3.XXXXXXXXX.com/media/attachments/450CodeCogsEqn3.gif"></XXXXXX> <p>XXXXXXX XXX x, XX get X.XXXXX (N.B.: you'll XXX two values, but you XXX't XXXX negative XXXXX). XX'XX not XXXX. This is how many X+ is given by glycine. As you XXX see XXXX XXX equation XXXXX, XXXXX H+ XX x + 10^-X</p> <p>So now, XXXXX step, XX XXXXX for the number of H+:</p> <figure><XXX src="https://XXXXXXXXXXXX.XX.amazonaws.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXX.XXX" data-s3="XXXXX://XXXXXXXXXXXX.s3.XXXXXXXXX.com/XXXXX/attachments/XXXXXXXXXXXXXXX.gif"></figure> <p>XXX XXX't XXXXXX! XXXXX's a XXX volume! It doesn't matter too much, XXX better XXXX than sorry:</p> <figure><img src="XXXXX://schoolsolver.s3.XXXXXXXXX.com/media/XXXXXXXXXXX/XXXXXXXXXXXXXXX.gif" data-s3="https://schoolsolver.XX.XXXXXXXXX.com/media/XXXXXXXXXXX/062CodeCogsEqn5.gif"></XXXXXX> <p>XXX XXXXXX get <strong>3.XX as XXXX XXX XX</XXXXXX>.</p>">
