XX XXX XXXXX XXXXXXX XX XXXX 1 XX XXX XXXXX XXX us XXXXXX was XXX that time XXXXXXXXX question cannot XX solved without the XXXXXX of XXXXXXXXXX
or XXXXX contains or XXXX radii
= 1050kg /m3
XXX XXXXXX of soil upto the root zone XX XXXXX XX 10 XXX x X.X = 50 m3
XXXX of the XXXX XXXXXX =ms =1050x XX = XXXXXXX
XXX available water on July XX can XX XXXX by plant =
water content July 15 = 29.X% XXXXX XXXXXX XXX XXXXX XXXXXXX below XX %
XX = 0.079 XXXXXX = XXXX.X kg
volume of XXXXX can XX XXXXXX = = 4.15 mX
XXX XX assume XXX XXXXX content on July X was XXX wilting XXXXX, i.e. XX%
XXXX density of soil XX equal to rd= XXXX XX/m3
the XXXXXX of the soil is equal XX XX x XXXX.X =XXXX
XX XXXXXX XX the XXXX ( XXXX solid + water XX + 22% w.c) = 1050x50=52500 XX
MS + MW = XXXXX
XXXXXX XX the XXXX now XX 15 July XXX open water content XX.X -XX is XXXXX to X.X % MS /MW = 0.XXX MX XX XXXXX to X.07 9x4303 2.XX = 3399.59
value of XXXX XXXXX is
C]
same XXXXXXXX in XXXX XXXX XX well
XX XXXXXXXX XXX XXXX XXX dry on Xst July Ms = 50500 kg
XXXXXX XX water @ XX =
on 15 July XXXXX XXXXXXX XX equal to 29.X %
XXXXXX of the XXXXX XX XXXXX XX XX /MS = 0. 299
MW = X.XXX XXXXX = XXXXX.5 kg
weight of water required 24150- S XXXXX.5 = XXXX.5 XX
XXXXXX = 8453.X / XXXX = 8.XX mX
XX XXXX the amount of rainfall XXXXX, XXX XXXXXX should XX XXXXXXX XX area XX XXX XXXXX XX XXXXX to
XXXXXXXX water content XX XXX XXXX building XXXXX on XXXX X
MS= XXXXX.79 XX
weight of XXXXX @ f c = XXXX X.XXX 0.XX= XXXX X.08 kg
XXXXXX of XXXXX @ 15th XXXX = for 303 2.X XXX 0.XXX= XXXXX . 8 XX
XXXXXX XX XXXXX needed= 19795.XXXX - 128 66.8= XXXX.28 XX
XXXXXX XX XXXXX to= 6292 X.XX/ 1000= 6.XXXX
in XXXXX of XXXXXXXX XXXXX= 6.93/ XXX= X.0693M= 6.93 XX CM