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= 2</b> </p> <p><img width="26" height="2" src="file:///C:/Users/jp%20computer/AppData/Local/Packages/oice_16_974fa576_32c1d314_f69/AC/Temp/msohtmlclip1/01/clip_imaXXXXX.XXX" v:shapes="XXXXXXXXXXXX"> </p> <p> </p> <p><b>m=2</b> </p> <p> </p> <p><b>XXXXXXXX in XXXXXXX XX y=XX+b where b XX XXXXXXXXX</b> </p> <p> </p> <p><b>XXX XXXXXXXXXXX it let we XXX point B(6,XX)</b> </p> <p> </p> <p><b>So XX XXXX XXXX y=11 XXX x=X XXXX put in the equation</b> </p> <p> </p> <p><b>Y=XX+b</b> </p> <p> </p> <p><b>11=2×6+b</b> </p> <p> </p> <p><b>b=-1</b> </p> <p> </p> <p> </p> <p><b>so XXXXXXXX is</b> <b>= X − X</b> </p> <p> </p> <ul><li><b>Find XXX XXXXXXXX XX the perpendicular bisector XX XXXX XX (Amks)</b> </li></XX> <p> </p> <p> </p> <p><b>XXX XXXXX so first XXXXXXXXX XXXXX of XXX XXXXXXXXXXXXX XXXXXXXX</b> </p> <p> </p> <table> <tbody><tr> <td> <p><b>Midpoint of AB XXX (</b> </p></td><td> <p> </p></td><td> <p><b>,</b> </p></td><td> <p> </p></td><td> <p><b>)=(5,9)</b> </p></td><td> <p> </p></td><td> <p> </p></td></tr> <tr> <td> <p> </p></td><td> <p> </p></td><td> <p> </p></td><td> <p> </p></td></tr> <tr> <td> <p><b>Slope of XXX XX can calculate from above XXXXXX as</b> </p></td><td> <p> </p></td><td> <p><b>= = X</b> </p></td></tr> <tr> <td> <p> </p></td></tr> <tr> <td> <p><b>m=2</b> </p></td><td> <p> </p></td><td> <p> </p></td><td> <p> </p></td><td> <p> </p></td><td> <p> </p></td><td> <p> </p></td></tr> </tbody></table> <p><XXX width="9" XXXXXX="X" src="file:///C:/Users/XX%20computer/XXXXXXX/XXXXX/XXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXXX/AC/Temp/XXXXXXXXXXXX/01/clip_image005.jpg" v:shapes="XXXXXXXXXXXX"> </p> <p> </p> <p><b>XXX XXXX XX the Perpendicular XXXXXXXX is−<img width="12" height="4" XXX="file:///X:/Users/XX%20computer/AppData/XXXXX/XXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXXX/XX/Temp/XXXXXXXXXXXX/XX/clip_image007.XXX" v:XXXXXX="XXXXXXXXXXXX"> XX AB so XXXX XX</b> <b>-<XXX width="8" height="4" src="XXXX:///C:/Users/jp%XXXXXXXXXX/XXXXXXX/Local/Packages/XXXXXXXXXXXXXXXXXXXXXXXXXXXXX/AC/Temp/msohtmlclip1/XX/XXXXXXXXXXXXX.jpg" v:shapes="_x0000_i1027"></b> </p> <p> </p> <p> </p> <p> </p> <p><b>XXX XX XXX calculate the XXXXXXXXX using (X, 9) XXX m as -X/X</b> </p> <p> </p> <p> </p> <p> </p> <p><b>XX XXX</b> </p> <p> </p> <p><b>9=− <XXX width="X" height="X" src="XXXX:///C:/Users/XX%20computer/AppData/XXXXX/Packages/oice_16_974fa576_32c1d314_f69/XX/XXXX/msohtmlclip1/01/XXXXXXXXXXXXX.jpg" v:XXXXXX="XXXXXXXXXXXX">×5+b</b> <b><XX> </b> </p> <table> <tbody><tr> <td> <p><b>XXX y =-12hence XXXXX XXX the XXXXXXXXXX of XXXXX C</b> </p></td></tr> </tbody></table> <p><b>b=11.5</b> </p> <p> </p> <p><b>now equation XX</b> </p> <p> </p> <p> </p> <p> </p> <p><b>Y= −<XXX width="9" XXXXXX="3" XXX="XXXX:///C:/XXXXX/XX%20computer/XXXXXXX/Local/XXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXXX/XX/XXXX/XXXXXXXXXXXX/01/clip_image005.XXX" v:XXXXXX="_x0000_i1029"> + XX.5 XX</b> </p> <p> </p> <p> </p> <p> </p> <XX><li><b>Given that AC is XXXXXXXXXXXXX XX XX and the equation of line XX XX y=-3x+XX, XXXX the co-XXXXXXXXX XX</b> </li></ul> <p><b>(XXX)</b> </p> <p> </p> <p><b>XXX’s XXXX the XXXXXXXX XX line XX which is perpendicular XX XXXX XX XXXXXX equation which XX y=2x-X perpendicular line XX XXX that has a XXXXXXXX, reciprocal slope XX another.</b> </p> <p> </p> <p><b>XX XX XXXX have equation y=-X/XX-1</b> </p> <p> </p> <p> </p> <p> </p> <p><b>As y will be XXXX XXX XXX XXXXX c XXXXXX XX use equation of XX or XXXXXXXX XX so we XXX put them XXXXX</b> </p> <p> </p> <p><b>-X/XX-X=-3x+45</b> </p> <p> </p> <p><b>X.XX=46</b> </p> <p> </p> <p><b>X=XX/X</b> </p>">
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