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Question Title:
Explain CMRR IN AN OP-AMP
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</XXXXXX><p>Aim of XXX XXXXXXX is to achieve the sum of v1,v2,XX in amplified form at output terminal.</p><p>Now XX XXX XX-XXX XXX a very XXXXX input XXXXXXXXX, there will no current going XXXX the Op-amp.</p><p>Therefore, i = i1+XX+i3 XX what flowing XX the output side. XXXX XXXXX XX a XXXXXXX XXXXX between the points X XXX B, there for voltage at these XXX XXXXX will be XXXXX. X XXXXX XX XX XXXXXX XXXXX the point A will XXXX be XX 0 XXXXX. Considering XXXXX XXXX dive XXXX analysis.<XX></p><XXXXXX><XXX XXX="XXXXX://schoolsolver.XX.XXXXXXXXX.XXX/media/XXXXXXXXXXX/370WhatsAppImage20200630at9.XX.XXXX.XXXX" XXXX-XX="https://schoolsolver.XX.XXXXXXXXX.com/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.52.35AM.jpeg"></XXXXXX><p>XXXXXXXX the currents XX XXXXX XXX XXXXXX side,</p><XXXXXX><XXX src="XXXXX://XXXXXXXXXXXX.s3.amazonaws.XXX/media/XXXXXXXXXXX/476WhatsAppImage20200630at9.XX.XXXX.XXXX" data-s3="XXXXX://schoolsolver.s3.amazonaws.XXX/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.52.XXXX.XXXX"></figure><p>To XXXXXXX XXXXXXX we will be setting,</p><figure><img src="XXXXX://schoolsolver.XX.XXXXXXXXX.com/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.54AM.XXXX" XXXX-s3="XXXXX://XXXXXXXXXXXX.s3.XXXXXXXXX.XXX/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.54AM.jpeg"></figure><p>XXXX XXX result will be,</p><XXXXXX><img XXX="https://schoolsolver.s3.amazonaws.XXX/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg" data-XX="XXXXX://XXXXXXXXXXXX.s3.XXXXXXXXX.com/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.53.XXXX.XXXX"></figure><p><br></p><p><XX></p><p>Now let's XXXX onto XXX XXXXXXXXXXXX XXXXXXXXX XXXXXXX.</p><p>The XXXXXXX XXXXX like,</p><XXXXXX><XXX XXX="XXXXX://schoolsolver.s3.XXXXXXXXX.XXX/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.53.XXXX.jpeg" data-XX="XXXXX://XXXXXXXXXXXX.s3.amazonaws.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg"></XXXXXX><p>Same XXXXXXX rule applies and XXX virtual short XXXXX XXXXXXX XX point A (VA) XXXX be XXXXX XX voltage at XXXXX B(XX).</p><p>Now XXXX on! XXXX's VB should XX?</p><p>XX XX w XXX voltage drop XXXXXX XX resistor, XXXXX is,</p><figure><img XXX="https://schoolsolver.s3.amazonaws.com/XXXXX/attachments/164WhatsAppImage20200630at9.54.00AM.jpeg" data-s3="XXXXX://XXXXXXXXXXXX.s3.amazonaws.XXX/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.54.XXXX.jpeg"></figure><p>Let's get into XXXXXXX XXXXXXXX,</p><p>The current i1 XX XXXX XX also flowing at XXX output side XXXXXXX XX hing input XXXXXXXXX XX XXX Op-amp, <XX></p><p>equating XXX XXXXXXX XX input and XXXXXX side,<XX></p><figure><XXX src="XXXXX://XXXXXXXXXXXX.s3.amazonaws.com/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.18AM.XXXX" data-s3="XXXXX://XXXXXXXXXXXX.XX.XXXXXXXXX.com/media/XXXXXXXXXXX/851WhatsAppImage20200630at9.54.18AM.XXXX"></figure><p>Solving algebraically,</p><XXXXXX><XXX src="https://XXXXXXXXXXXX.XX.XXXXXXXXX.XXX/media/attachments/463WhatsAppImage20200630at9.54.32AM.jpeg" XXXX-XX="https://schoolsolver.s3.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg"></figure><p>XX, XXXXXX XXXXXXX becomes,</p><figure><XXX XXX="XXXXX://XXXXXXXXXXXX.s3.amazonaws.com/XXXXX/attachments/973WhatsAppImage20200630at9.54.XXXX.jpeg" data-s3="https://schoolsolver.XX.amazonaws.XXX/media/XXXXXXXXXXX/973WhatsAppImage20200630at9.XX.45AM.jpeg"></figure><p>Now to achieve the XXXXXXXXXXXX XXXXXXXXX XX XXXXXX XX XXX following,</p><figure><img XXX="https://schoolsolver.s3.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.56AM.jpeg" XXXX-s3="XXXXX://XXXXXXXXXXXX.s3.amazonaws.XXX/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.56AM.jpeg"></figure><p>Now XXX output becomes,</p><XXXXXX><XXX src="https://XXXXXXXXXXXX.XX.amazonaws.XXX/media/attachments/026WhatsAppImage20200630at9.55.XXXX.jpeg" data-XX="XXXXX://schoolsolver.XX.XXXXXXXXX.XXX/XXXXX/attachments/026WhatsAppImage20200630at9.XX.XXXX.jpeg"></figure><p>XXXXXXXXXXXX XXXXXXXXX achieved!!</p><p><XX></p><p><br></p><p>Let's move XXXX XXX XXXXXXX,</p><p>Looking XXX XXXXXXX, it's XXXX a XXXXXXX amplifier XXX XX just XXX the XXXXXXXX value given in the XXXXXXX into XXX XXXXXXXX XX got,</p><figure><img XXX="https://XXXXXXXXXXXX.XX.amazonaws.XXX/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.17.16AM.XXXX" data-XX="https://schoolsolver.XX.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.16AM.XXXX"></XXXXXX><p>where,</p><figure><img src="XXXXX://XXXXXXXXXXXX.XX.XXXXXXXXX.XXX/media/attachments/807WhatsAppImage20200630at10.XX.XXXX.XXXX" data-s3="XXXXX://XXXXXXXXXXXX.s3.amazonaws.com/media/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg"></XXXXXX><p>XXXXXXX XXXXX XXXXXX,</p><figure><XXX src="XXXXX://schoolsolver.XX.amazonaws.com/XXXXX/XXXXXXXXXXX/681WhatsAppImage20200630at10.XX.XXXX.XXXX" XXXX-XX="https://XXXXXXXXXXXX.s3.amazonaws.XXX/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.19.34AM.XXXX"></figure><p>XXXXXX will XX -40V.<br></p><p><br></p><p><XX></p>">
