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Explain CMRR IN AN OP-AMP
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</figure><p>Aim XX XXX XXXXXXX XX to achieve the XXX of v1,v2,XX in amplified XXXX XX output terminal.</p><p>XXX XX the XX-amp has a XXXX XXXXX XXXXX XXXXXXXXX, XXXXX will no XXXXXXX going XXXX the Op-XXX.</p><p>XXXXXXXXX, i = i1+i2+i3 is XXXX flowing XX the XXXXXX side. XXXX there XX a virtual XXXXX between the points X and X, there for XXXXXXX at XXXXX XXX nodes XXXX XX equal. X XXXXX is at XXXXXX there XXX XXXXX A XXXX XXXX be at X volts. Considering these lets XXXX into analysis.<XX></p><figure><img XXX="https://schoolsolver.s3.XXXXXXXXX.XXX/XXXXX/XXXXXXXXXXX/370WhatsAppImage20200630at9.52.XXXX.XXXX" data-XX="XXXXX://XXXXXXXXXXXX.XX.amazonaws.com/media/attachments/370WhatsAppImage20200630at9.52.35AM.XXXX"></figure><p>Equating XXX currents XX input and XXXXXX side,</p><XXXXXX><XXX XXX="https://schoolsolver.XX.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/476WhatsAppImage20200630at9.52.55AM.XXXX" XXXX-XX="https://schoolsolver.XX.amazonaws.XXX/media/attachments/476WhatsAppImage20200630at9.XX.XXXX.jpeg"></XXXXXX><p>XX achieve XXXXXXX we XXXX be XXXXXXX,</p><XXXXXX><img XXX="https://schoolsolver.s3.XXXXXXXXX.XXX/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.07.XXXX.jpeg" data-XX="XXXXX://schoolsolver.s3.XXXXXXXXX.XXX/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.07.54AM.XXXX"></XXXXXX><p>Then XXX result XXXX be,</p><figure><XXX src="https://XXXXXXXXXXXX.XX.amazonaws.XXX/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.53.XXXX.XXXX" data-XX="XXXXX://schoolsolver.s3.XXXXXXXXX.XXX/media/XXXXXXXXXXX/590WhatsAppImage20200630at9.XX.28AM.XXXX"></figure><p><XX></p><p><XX></p><p>Now let's XXXX XXXX the differential XXXXXXXXX XXXXXXX.</p><p>XXX XXXXXXX looks XXXX,</p><XXXXXX><img XXX="https://XXXXXXXXXXXX.s3.amazonaws.XXX/media/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.53.47AM.XXXX" data-XX="https://XXXXXXXXXXXX.XX.amazonaws.com/media/attachments/074WhatsAppImage20200630at9.XX.47AM.jpeg"></XXXXXX><p>XXXX XXXXXXX rule XXXXXXX and XXX virtual short XXXXX XXXXXXX XX point A (XX) will XX equal XX XXXXXXX at XXXXX B(VB).</p><p>XXX hold on! what's XX should be?</p><p>VB XX w the voltage drop across R3 XXXXXXXX, XXXXX XX,</p><figure><XXX src="XXXXX://schoolsolver.s3.amazonaws.XXX/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.XXXX.jpeg" XXXX-XX="https://schoolsolver.XX.XXXXXXXXX.XXX/XXXXX/attachments/164WhatsAppImage20200630at9.XX.00AM.jpeg"></XXXXXX><p>XXX's XXX XXXX current analysis,</p><p>XXX XXXXXXX i1 is what XX also XXXXXXX XX the XXXXXX side XXXXXXX of hing XXXXX impedance of XXX Op-XXX, <XX></p><p>XXXXXXXX XXX XXXXXXX of XXXXX and output XXXX,<br></p><XXXXXX><XXX XXX="XXXXX://XXXXXXXXXXXX.XX.amazonaws.XXX/XXXXX/XXXXXXXXXXX/851WhatsAppImage20200630at9.XX.XXXX.jpeg" XXXX-XX="XXXXX://XXXXXXXXXXXX.XX.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXX.54.XXXX.XXXX"></XXXXXX><p>XXXXXXX XXXXXXXXXXXXX,</p><XXXXXX><img src="XXXXX://schoolsolver.s3.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/463WhatsAppImage20200630at9.XX.32AM.XXXX" data-s3="XXXXX://XXXXXXXXXXXX.s3.XXXXXXXXX.com/media/XXXXXXXXXXX/463WhatsAppImage20200630at9.XX.32AM.jpeg"></XXXXXX><p>XX, output voltage becomes,</p><XXXXXX><XXX src="XXXXX://schoolsolver.XX.XXXXXXXXX.com/XXXXX/attachments/973WhatsAppImage20200630at9.54.45AM.XXXX" XXXX-s3="https://XXXXXXXXXXXX.XX.amazonaws.com/XXXXX/attachments/973WhatsAppImage20200630at9.XX.45AM.jpeg"></XXXXXX><p>Now to achieve the differential operation XX should do the following,</p><XXXXXX><XXX XXX="XXXXX://schoolsolver.s3.XXXXXXXXX.com/media/XXXXXXXXXXX/568WhatsAppImage20200630at9.XX.56AM.jpeg" XXXX-XX="https://XXXXXXXXXXXX.s3.XXXXXXXXX.com/media/attachments/568WhatsAppImage20200630at9.54.56AM.XXXX"></XXXXXX><p>Now XXX output becomes,</p><XXXXXX><XXX src="XXXXX://XXXXXXXXXXXX.XX.XXXXXXXXX.XXX/media/attachments/026WhatsAppImage20200630at9.XX.XXXX.jpeg" XXXX-s3="XXXXX://XXXXXXXXXXXX.s3.amazonaws.XXX/XXXXX/attachments/026WhatsAppImage20200630at9.XX.09AM.XXXX"></figure><p>Differential operation achieved!!</p><p><br></p><p><XX></p><p>XXX's move onto the XXXXXXX,</p><p>Looking the XXXXXXX, it's just a XXXXXXX XXXXXXXXX XXX XX XXXX XXX XXX required XXXXX XXXXX in the problem XXXX XXX equation we got,</p><XXXXXX><XXX src="https://schoolsolver.XX.XXXXXXXXX.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.17.16AM.jpeg" data-XX="https://XXXXXXXXXXXX.XX.amazonaws.XXX/XXXXX/XXXXXXXXXXX/798WhatsAppImage20200630at10.XX.XXXX.jpeg"></figure><p>XXXXX,</p><XXXXXX><img XXX="https://schoolsolver.XX.amazonaws.com/XXXXX/XXXXXXXXXXX/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.38AM.XXXX" data-XX="https://XXXXXXXXXXXX.s3.amazonaws.XXX/media/XXXXXXXXXXX/807WhatsAppImage20200630at10.XX.38AM.XXXX"></figure><p>XXXXXXX XXXXX XXXXXX,</p><XXXXXX><XXX XXX="XXXXX://XXXXXXXXXXXX.s3.XXXXXXXXX.XXX/media/attachments/681WhatsAppImage20200630at10.19.XXXX.XXXX" data-XX="https://schoolsolver.s3.amazonaws.com/XXXXX/attachments/XXXXXXXXXXXXXXXXXXXXXXXXXXXX.XX.34AM.XXXX"></figure><p>XXXXXX will XX -XXX.<br></p><p><br></p><p><br></p>">
