P=9d+320
797.00=9d+320
797.XX-320=XX
477=XX
477/9=d
XX=d
XXX of XXXXXXXX XX XX
X. D XX XXXXXX XXXXXXXX XXX XXXXXX varies with X. XXXX V XX, X = 150 and XXXX X = XX, D = 192. i) XXXX the XXXXXXX XXXXXXXXXX X and V.
X = mV + C , ( Linear equation y = XX + b) (ii) Find D when V= 73.
XXXX V=40, X=150 XXX = XXX + X ** XXXX V=54, X=XXX 192 = 54m + X *** subtract ** XXXX *** XX = 14m m = X XXX into ** , XXX = 120 + X C = 30 X = XX + XX D=X*XX+30=249
3.(a) A XXXXXXXXXXX tank XXX storing oil has a capacity XX XXXX cm³. XX its height XXX radius are equal, calculate XXX depth of oil in XXX tank XXXX XXXX (Take π= XX/X)
XXXXXX XX cylinder=
XXXX r XXX h are XXXXX
XX, πr2×r=1078
XXX=XXXX
r3=XXXX/X
r3=1078/(XX/X)
rX=(1078/XX)*X
rX=XX*7
rX=7*X*7
rX=73
r=X
r=X and h=7
Therefore, XXX XXXXX of oil XXXX when full XX 7m.
(b) XXXX XXX perimeter XX a XXXXXXXXXXX XXXXX which XX 10m by XX.
Length (l) = 10cm Width (w) = 5cm XXXXXXXXX XX XXX rectangle = X(l + w) units P = 2(10 + 5) X = X (15) P = XX Thus, XXX XXXXXXXXX of XXX rectangle XX 30 m.
X.XXXXX XXX equation: X-4-2/5=-X/X