P=9d+320
797.00=9d+320
797.00-XXX=9d
XXX=XX
477/X=d
XX=d
XXX of articles XX XX
2. D XX XXXXXX constant XXX partly varies XXXX X. When V XX, X = XXX and XXXX V = 54, D = XXX. i) XXXX the formula connecting X and X.
X = mV + X , ( Linear equation y = mx + b) (XX) Find D XXXX V= XX.
XXXX X=40, X=XXX XXX = XXX + C ** XXXX V=XX, X=XXX 192 = 54m + C *** XXXXXXXX ** XXXX *** 42 = 14m m = 3 XXX XXXX ** , XXX = 120 + X C = 30 D = XX + 30 X=3*73+30=249
X.(a) A cylindrical XXXX XXX storing XXX has a capacity XX XXXX cm³. If XXX height XXX radius are equal, calculate XXX XXXXX of XXX in XXX XXXX XXXX XXXX (XXXX π= XX/X)
Volume of XXXXXXXX=
Here r and h XXX equal
So, XXX×r=XXXX
XXX=XXXX
r3=XXXX/π
rX=XXXX/(XX/X)
r3=(XXXX/XX)*7
rX=XX*7
r3=X*X*7
rX=X3
r=X
r=7 XXX h=X
Therefore, the XXXXX XX oil tank when XXXX XX XX.
(b) XXXX XXX perimeter XX a XXXXXXXXXXX XXXXX XXXXX is 10m by 5m.
XXXXXX (l) = 10cm XXXXX (w) = 5cm XXXXXXXXX XX XXX XXXXXXXXX = X(l + w) units P = 2(10 + X) X = X (15) P = 30 Thus, XXX XXXXXXXXX of the rectangle is 30 m.
4.XXXXX XXX equation: X-4-X/X=-X/X