P=9d+320
797.00=9d+320
XXX.XX-XXX=9d
477=XX
477/X=d
53=d
The of articles is XX
2. D XX XXXXXX constant and partly varies XXXX X. When V XX, D = 150 XXX when X = 54, D = XXX. i) XXXX XXX formula XXXXXXXXXX D and X.
X = mV + C , ( XXXXXX XXXXXXXX y = mx + b) (ii) Find D XXXX X= 73.
When X=40, D=150 XXX = XXX + C ** When X=XX, X=XXX XXX = 54m + C *** XXXXXXXX ** XXXX *** XX = 14m m = X XXX XXXX ** , 150 = 120 + X C = XX D = XX + 30 X=3*73+30=249
3.(a) X XXXXXXXXXXX tank for storing XXX XXX a XXXXXXXX XX XXXX XXX. If its XXXXXX XXX XXXXXX XXX equal, XXXXXXXXX XXX depth of oil in XXX tank XXXX XXXX (Take X= 22/X)
XXXXXX of XXXXXXXX=
XXXX r and h are XXXXX
So, XXX×r=XXXX
πrX=XXXX
rX=XXXX/X
r3=XXXX/(XX/7)
r3=(XXXX/22)*X
r3=49*X
r3=X*7*X
r3=73
r=X
r=7 XXX h=X
Therefore, the XXXXX XX oil tank when full is 7m.
(b) XXXX XXX XXXXXXXXX of a XXXXXXXXXXX XXXXX XXXXX XX 10m XX XX.
Length (l) = XXXX XXXXX (w) = 5cm Perimeter of XXX rectangle = X(l + w) XXXXX X = 2(XX + X) X = X (XX) X = XX XXXX, the perimeter of XXX rectangle is 30 m.
X.Solve XXX XXXXXXXX: X-X-2/5=-X/2