so XX puting the values in XXX XXXXXXX,
XXXX= 22/7 * h * h* h ( as h=r)
> 1078*(X/22) = h*h*h
&XX; h^X = 343
&XX; h=7
so XXX XXXXX of the XXX XXXX XX 7cm.
b)here,
XXXXXX=10m
XXXXXXX=XX
perimeter XX XXX rectangle XX = X*(XXXXXX + XXXXXXX)
so, XXXXXXXXX=2*(XX+5)= X*15=XXX
4)
so, x= 44/15