so by puting XXX XXXXXX in the XXXXXXX,
XXXX= XX/X * h * h* h ( XX h=r)
&XX; 1078*(X/22) = h*h*h
> h^3 = 343
&XX; h=X
so XXX XXXXX XX the XXX XXXX is 7cm.
b)XXXX,
length=10m
breadth=5m
perimeter of the rectangle XX = 2*(length + breadth)
so, perimeter=2*(10+X)= X*XX=30m
X)
so, x= 44/XX