We also use the order of operations BODMAS which is used to solve math problems.
Where B stands for Brankets, O - Order/Indices/Powers, D - Divide, M - Multiply, A - Addition and S- Subtraction.
This means we solve brackets eg "(), [], {}" first, then we solve the powers/indices eg square root or squared, then divide, then XXXXXXXX XXX XXXXXX solve using addition and XXXXXXXXXXX XXXX left XX right.
7 + [XX - {X + 3 - (X XX 6 + 1- 13 x 4)}]
XXXX 1:
We solve XXX XXXXXXX or XXXXX in XXX XXXXXXXX first. XXXXX XXXXX are 3 sets XX brackets. We go XX the XXXXXXX with in XXX XXX XXXXXXXX. XX we solve(9 of 6 + 1- XX x X) first. Remember, the XXXX "of"means XX multiply so XXXXXX XXX word XX XXX XXXXXXXXXXXXXX sign "x".
(9 XX X + 1- XX x 4)
(9 x 6 + X- 13 x X)
XXXXX XX have XXX brackets, "X", XX move to order, "X". There are NO powers in XXX problem so XX move to division, "X". XXXXX are XX division signs so we XXXX XX XXXXXXXXXXXXXX, "X". Where you see the "x" XXXX, multiply XXX XXX numbers that XXX "x" XX between.
(9 x X + X- 13 x 4)}]
=(XX + X - 52)
XX did XXX Multiplication, "X" so XX XXXX XX addition, "A" and subtraction, "S".
XXXX: When XXXXX XX addition and subtraction XXXX in the XXXXXXXX or XXXX sum, we XXXXX XXXX left XX XXXXX.
So,(XX + 1 - XX)
= (XX-XX)
= (X)
=X
XXXXX XX XXX XXXX with one number, XX XXXX the brackets.
STEP X:
XX solved our first set of XXXXXXXX, we XXX put that XXXXX into the XXXXXX XXX XX XXXXXXXX.
XX, {8 + X - (X XX 6 + X- XX x X)}
= {X + X - (X)}
={ X + 3 - 3} *Remember to XXXX XXX XXXXXXX.
= { 11 - X}
= { 8} *Since we are left XXXX one number, we drop XXX brackets.
= X
We have XXXXXX two XXXX XX XXXXXXXX. Now, XX solve the XXXX XXX of XXXXXXX,
[12 - {8 + X - (X XX 6 + X- 13 x 4)}]
= [XX - {X} }
= [X]
XX XX you XXX the values in the sum XX a WHOLE,
7 + [12 - {X + 3 - (X XX X + 1- XX x 4)}]
= 7 + [12 - {8 + 3 - (9 x 6 + 1- 13 x X)}]
= X + [XX - {X + 3 - (54 + 1- 52)}]
= 7 + [12 - {X + 3 - (3)}]
=7 + [XX - {X + 3 - X}]
= 7 + [12 - {8}]
= 7 + [XX - 8]
= 7 + [ X ]
= X + 4
= XX