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sir what does this mean
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<p>We also use the order of operations BODMAS which is used to solve math problems.</p> <p>Where B stands for Brankets, O - Order/Indices/Powers, D - Divide, M - Multiply, A - Addition and S- Subtraction.</p><p>This means we solve brackets eg "(), [], {}" first, then we solve the powers/indices eg square root or squared, then dXXXXX, then multiply XXX lastly XXXXX using addition XXX XXXXXXXXXXX from left to right.</p><p><XX></p> <p>X + [XX - {8 + 3 - (9 XX X + X- XX x 4)}]</p> <p><br></p> <p>XXXX 1:</p> <p>We XXXXX XXX XXXXXXX or terms in the XXXXXXXX first. XXXXX XXXXX XXX 3 XXXX XX XXXXXXXX. We go to XXX XXXXXXX with in the two XXXXXXXX. XX we solve(9 of 6 + X- 13 x 4) first. Remember, the word "XX"means to multiply so XXXXXX XXX XXXX XX XXX XXXXXXXXXXXXXX sign "x".</p> <p>(X XX 6 + 1- XX x X)<XX></p> <p>(X x X + X- 13 x 4)<br></p> <p>XXXXX we have our XXXXXXXX, "B", XX move XX order, "O". There XXX XX XXXXXX in the XXXXXXX so we XXXX XX division, "X". There XXX XX XXXXXXXX XXXXX so we XXXX to multiplication, "M". Where you XXX XXX "x" XXXX, XXXXXXXX XXX two numbers that the "x" XX between.</p> <p>(X x 6 + X- 13 x X)}]<XX></p> <p>=(XX + 1 - 52)</p> <p><XX></p> <p>XX did XXX Multiplication, "X" so we XXXX XX XXXXXXXX, "A" XXX XXXXXXXXXXX, "S".</p> <p>NOTE: XXXX there is addition XXX subtraction only in XXX brackets or XXXX XXX, we solve from XXXX XX right.</p> <p>XX,(54 + 1 - XX)</p> <p>= (55-52)</p> <p>= (X)</p> <p>=3</p> <p>XXXXX XX are left XXXX XXX number, XX XXXX the XXXXXXXX.</p> <p><br></p> <p>STEP X:</p> <p>We solved XXX XXXXX XXX of brackets, XX XXX put XXXX value XXXX XXX XXXXXX XXX of brackets.</p> <p>So, {8 + X - (X of 6 + 1- XX x 4)}</p> <p>= {X + X - (X)}</p> <p>={ X + X - 3} *XXXXXXXX XX XXXX the XXXXXXX.</p> <p>= { XX - 3}</p> <p>= { X} *Since XX are left XXXX XXX XXXXXX, XX XXXX the XXXXXXXX.</p> <p>= 8</p> <p><XX></p> <p>XX have solved two XXXX XX XXXXXXXX. Now, we XXXXX XXX XXXX set XX XXXXXXX,</p> <p>[12 - {8 + 3 - (X of X + X- 13 x X)}]<br></p> <p>= [XX - {8} }</p> <p>= [X]</p> <p>= 4</p> <p><br></p> <p>So XX you put XXX values in XXX sum as a WHOLE,</p> <p>7 + [XX - {8 + 3 - (9 XX X + X- XX x 4)}]</p> <p>= 7 + [12 - {X + X - (9 x X + 1- XX x 4)}]<XX></p> <p>= 7 + [XX - {8 + X - (XX + 1- 52)}]<XX></p> <p>= X + [12 - {8 + 3 - (X)}]<XX></p> <p>=7 + [XX - {X + 3 - 3}]<XX></p> <p>= X + [12 - {8}]</p> <p>= 7 + [12 - 8]<br></p> <p>= 7 + [ X ]</p> <p>= 7 + X</p> <p>= 11</p> <p></p> <p><br></p> <p><br></p>">
