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sir what does this mean
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<p>We also use the order of operations BODMAS which is used to solve math problems.</p> <p>Where B stands for Brankets, O - Order/Indices/Powers, D - Divide, M - Multiply, A - Addition and S- Subtraction.</p><p>This means we solve brackets eg "(), [], {}" first, then we solve the powers/indices eg square root or squared, then divide, then XXXXXXXX and XXXXXX XXXXX using XXXXXXXX XXX XXXXXXXXXXX XXXX XXXX to XXXXX.</p><p><XX></p> <p>X + [12 - {X + 3 - (X of X + 1- 13 x 4)}]</p> <p><XX></p> <p>STEP 1:</p> <p>We solve the XXXXXXX or terms in XXX brackets XXXXX. XXXXX there XXX 3 XXXX of brackets. We XX XX XXX bracket with in the two brackets. XX XX XXXXX(X of 6 + 1- XX x 4) first. Remember, the XXXX "of"means to multiply so XXXXXX XXX XXXX XX the XXXXXXXXXXXXXX sign "x".</p> <p>(X XX X + 1- 13 x X)<br></p> <p>(X x X + X- XX x 4)<XX></p> <p>XXXXX XX XXXX our XXXXXXXX, "B", we XXXX XX order, "X". There XXX NO powers in XXX XXXXXXX so XX XXXX XX division, "X". There are XX XXXXXXXX signs so we move to multiplication, "X". Where you see XXX "x" sign, multiply the XXX numbers that the "x" is XXXXXXX.</p> <p>(X x 6 + X- XX x X)}]<XX></p> <p>=(XX + 1 - XX)</p> <p><br></p> <p>XX did the Multiplication, "X" so we move to XXXXXXXX, "A" and XXXXXXXXXXX, "S".</p> <p>NOTE: When there XX XXXXXXXX XXX subtraction only in the XXXXXXXX or math sum, XX solve from XXXX XX XXXXX.</p> <p>So,(54 + X - XX)</p> <p>= (55-52)</p> <p>= (X)</p> <p>=3</p> <p>Since XX are XXXX with XXX number, we XXXX XXX XXXXXXXX.</p> <p><br></p> <p>XXXX X:</p> <p>XX solved XXX first set of XXXXXXXX, XX can XXX XXXX XXXXX XXXX the XXXXXX XXX of XXXXXXXX.</p> <p>XX, {8 + X - (X of 6 + 1- 13 x 4)}</p> <p>= {X + 3 - (3)}</p> <p>={ X + 3 - 3} *XXXXXXXX to drop the bracket.</p> <p>= { 11 - 3}</p> <p>= { 8} *Since XX are left XXXX one XXXXXX, we XXXX XXX XXXXXXXX.</p> <p>= 8</p> <p><br></p> <p>We have XXXXXX XXX XXXX XX XXXXXXXX. Now, XX XXXXX XXX XXXX set XX brackts,</p> <p>[XX - {8 + 3 - (9 XX 6 + X- XX x X)}]<br></p> <p>= [12 - {8} }</p> <p>= [4]</p> <p>= X</p> <p><XX></p> <p>XX if you XXX the values in the XXX XX a WHOLE,</p> <p>7 + [XX - {X + X - (X XX X + 1- 13 x 4)}]</p> <p>= X + [XX - {X + 3 - (9 x 6 + X- XX x X)}]<br></p> <p>= 7 + [12 - {X + 3 - (XX + X- 52)}]<br></p> <p>= 7 + [XX - {8 + X - (3)}]<XX></p> <p>=X + [12 - {X + X - 3}]<br></p> <p>= X + [12 - {X}]</p> <p>= 7 + [12 - 8]<br></p> <p>= 7 + [ 4 ]</p> <p>= 7 + 4</p> <p>= XX</p> <p></p> <p><br></p> <p><br></p>">
