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sir what does this mean
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<p>XXXXX is X*X= 54, XX*X= 52 in XXX XXXXX step</p> <p>7+[XX-{X+3-(XX+1-52)}]</p> <p>in the XXXX step XX look XXX "X" in BODMAS which XX divison XXXXXXX XXXXXX brackets, XXXXX XXXXX XXX no division, continue XXXX XXXX which XX "X" which is XXXXXX and XXX XXXXXXXXXXXXX brackets, so XXXX XX "X" XXXXX is additions is XXXXX itpresent XXXXXX XXXXXXXX, XXXXX is XX+1= 55 , in XXX XXXXX step<XX><br></p> <p>7+[XX-{X+3-(XX-52)}]</p> <p>in the next order we should look for "S" in BODMAS which is subtractionpresent inside brackets, which is XX-52, solve as in next step</p> <p><br>X+[XX-{8+3-(X)}]</p> <p>XXX eliminating XXX brackets again , XXX next XXXX<XX>X+[XX-{X+3-X}]</p> <p>so again look XXX BODMAS, XXXXX there is no divison and multiplication ,XXXX XX "X" which is XXXXXXXXX XX XXXXX itpresent inside XXXXXXXX, XXXXX XX 8+3=XX<br></p> <p>7+[12-{11-3}]<XX></p> <p>so again look for BODMAS, XXXXX XXXXX XX XX divison andmultiplication and addition in the brackets, so solve for "S" XXXXXXXXXXX, XXXXX XX 11-3=X, XX show XXXXX</p> <p>7+[XX-X]</p> <p>now XXXXX solve,XXXX for BODMAS, XXXXX there XX no divison XXXXXXXXXXXXXXXXX XXX addition in the brackets, so XXXXX XXX "S" XXXXXXXXXXX, XXXXX is XX-8=4, as shown below</p> <p><br>7+X</p> <p>XXX add<br>XX</p> <p>so XXX XXXXXX is 11</p>">
