XXXXX XX 9*6= XX, XX*X= XX in the XXXXX step
7+[XX-{8+X-(XX+1-52)}]
in XXX next XXXX XX XXXX XXX "D" in XXXXXX which is divison XXXXXXX inside brackets, since there are XX XXXXXXXX, continue with next XXXXX is "M" which is XXXXXX and not presentinside brackets, so XXXX XX "X" XXXXX is additions XX XXXXX itpresent XXXXXX brackets, which is 54+1= XX , in the XXXXX step
7+[XX-{X+X-(XX-52)}]
in XXX next order we should look for "S" in BODMAS XXXXX XX subtractionpresent XXXXXX brackets, which XX 55-52, XXXXX as in XXXX XXXX
X+[XX-{8+X-(3)}]
now XXXXXXXXXXX the XXXXXXXX XXXXX , XXX next XXXX7+[12-{X+3-3}]
so again look for XXXXXX, XXXXX XXXXX XX no divison and XXXXXXXXXXXXXX ,next XX "X" which is additions XX XXXXX XXXXXXXXX inside XXXXXXXX, which XX 8+3=11
X+[XX-{XX-3}]
so again look XXX XXXXXX, XXXXX there is XX divison XXXXXXXXXXXXXXXXX and addition in the brackets, so XXXXX XXX "S" XXXXXXXXXXX, which is 11-X=8, as show below
7+[XX-X]
XXX again solve,XXXX for BODMAS, since there is XX divison andmultiplication XXX XXXXXXXX in XXX XXXXXXXX, so XXXXX XXX "S" XXXXXXXXXXX, XXXXX XX 12-8=X, XX shown below
7+X
XXX add11
so the XXXXXX is 11