XXXXX is X*6= 54, XX*4= XX in XXX below XXXX
7+[XX-{8+3-(XX+1-XX)}]
in XXX next step we look for "D" in BODMAS which is divison XXXXXXX inside brackets, XXXXX XXXXX XXX no division, XXXXXXXX with next which XX "M" XXXXX is XXXXXX and XXX presentinside XXXXXXXX, so XXXX is "A" XXXXX XX additions XX solve itpresent XXXXXX XXXXXXXX, which is 54+1= XX , in the below step
7+[XX-{X+X-(55-XX)}]
in the next order we XXXXXX look for "S" in XXXXXX XXXXX is subtractionpresent XXXXXX brackets, XXXXX XX XX-XX, XXXXX as in XXXX XXXX
X+[12-{X+X-(3)}]
XXX eliminating the XXXXXXXX again , XXX XXXX step7+[12-{8+X-3}]
so XXXXX XXXX for BODMAS, XXXXX XXXXX is no XXXXXXX and multiplication ,next is "A" which XX additions XX XXXXX XXXXXXXXX inside XXXXXXXX, XXXXX is 8+3=XX
X+[XX-{XX-3}]
so again XXXX for XXXXXX, since there is no XXXXXXX andmultiplication XXX XXXXXXXX in the XXXXXXXX, so solve for "S" XXXXXXXXXXX, XXXXX XX 11-3=8, as show XXXXX
7+[12-8]
XXX XXXXX XXXXX,XXXX for BODMAS, XXXXX XXXXX is XX XXXXXXX andmultiplication XXX addition in XXX XXXXXXXX, so solve for "S" XXXXXXXXXXX, which XX XX-8=4, XX shown below
X+X
now add11
so XXX answer XX XX