XXXXX XX X*6= XX, XX*X= XX in XXX below step
7+[XX-{8+X-(XX+X-XX)}]
in XXX next XXXX we XXXX for "D" in XXXXXX XXXXX is divison XXXXXXX XXXXXX brackets, since XXXXX are XX XXXXXXXX, continue with XXXX which XX "M" XXXXX is solved XXX XXX XXXXXXXXXXXXX brackets, so next is "A" XXXXX XX additions is XXXXX itpresent inside XXXXXXXX, which is XX+1= XX , in the XXXXX XXXX
7+[12-{8+3-(XX-XX)}]
in XXX next order XX XXXXXX look XXX "S" in BODMAS XXXXX XX subtractionpresent inside XXXXXXXX, which is 55-XX, solve as in next step
X+[XX-{8+X-(X)}]
now eliminating the brackets again , the next XXXXX+[XX-{8+X-3}]
so again look for BODMAS, XXXXX there XX no divison and XXXXXXXXXXXXXX ,XXXX XX "A" which XX XXXXXXXXX XX XXXXX itpresent XXXXXX brackets, which XX X+3=XX
7+[12-{XX-3}]
so again XXXX XXX XXXXXX, XXXXX there XX XX XXXXXXX XXXXXXXXXXXXXXXXX XXX XXXXXXXX in the XXXXXXXX, so solve for "S" XXXXXXXXXXX, which XX XX-X=8, as show XXXXX
X+[12-8]
XXX XXXXX solve,XXXX for BODMAS, XXXXX XXXXX XX no divison XXXXXXXXXXXXXXXXX and addition in XXX brackets, so XXXXX XXX "S" subtraction, XXXXX is XX-X=4, as shown below
X+X
XXX add11
so XXX XXXXXX XX XX