The df(Between) = X The df(Within) = 12 The XXXXXXXXX= 5700.X
XXbetween = 2850.2 SSwithin= XXXX
XXwithin= XXX.X XXX F XXXXXXXXX = 3.6101
XXXXX:The XXXXXX among the XXXXXXXXX XXXXXX XXXXXXXXX.
The null and alternative hypothesis is:
H1: XX XXXXX one of the mean is not equal.
Level of XXXXXXXXXXXX = 0.05
XXXX XXXXXXXXX F = X.6101
XXXXXXXX XXXXX = 3.XXXX
XXXX XXXXXXXXX F < XXXXXXXX value XX fail XX reject XXXX XXXXXXXXXX.
XXXXXXXXXX: XXX XXXXXX among XXX XXXXXXXXX groups XXX the same.