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A. x/3 - 7 = -2 x/3 = 5 x = 15 |
B. 4x + 3 = -17 4x = -20 x = -5 |
C. 5x + 12 = 87 x = (87 - 12)/5 x = 15 |
D. (x+7)/3 = 2 x+7 = 6 x = -1 |
E. -6 (x-1) = 18 -6 = 18x - 18 18x = 12 x = 12/18 x = 2/3 = 0.66 |
F 8x + 2 = -2 8x = -2 -2 x = -1/2 = -0.5 |
G (3/4)x - 5 = 4 (3/4)x = 9 x = 9 * (4/3) x = 12 |
H (-5/2)x + 6 = 1 (-5/2)x = -5 x = (-5)/(-5/2) x = 2 |
I 6x + 3 = -1 6x = -4 x = -(4/6) = -(2/3) = -0.66 |
Exercise #2
5(x-3) + 2 = 7
8
5(x-3) + 16 = 56
5(x-3) = 40
x-3= 8
x = 11
Exercise #3
(a) 5(x-3) + 2x = 4(x+3)
5x - 15 + 2x = 4x + 12
7x - 15 = 4x + 12
(b) 7x - 15 = 4x + 12
3x = 27
x = 9
Let x = 9 for 5(x-3) + 2x = 4(x+3)
5(9-3) + 2(9) = 4((9)+3)
30 + 18 = 48
The equation holds true.
Exercise #4
(a) 7(x-2)-3(x+3) = 5(x-3) + x
7x - 14 - 3x - 9 = 5x - 15 + x
4x - 23 = 6x - 15
2x = -8
x = -4
(b) 9 - 6(x+1) = 2(x-4) + 27
9 - 6x - 6 = 2x - 8 + 27
3 - 6x = 2x + 19
8x = 3-19
x = (-16)/8
x = -2
Fluency
1.
a. 7x - 15 = 1
7x = 16
x = 16/7 = 2.28
b. (x+2)/4 = -2
x+2 = -8
x = -10
c. (-3/5)x + 2 = 7
(-3/5)x = 5
x = -8.333 OR -8 and 1/3
2.
a. 5(x+1) + 4 = 4
6
5(x+1) + 4 = 24
5x + 9 = 24
5x = 15
x = 3
b. 5(x-3) + 2 = 7
8
5(x-3) + 16 = 56
5x - 15 + 16 = 56
5x + 1 = 56
5x = 55
x = 11
c. -(3/2)x + 2 = -4
-(3/2)x = -6
(3/2)x = 6
x = 4
d. 5(x+1) - 2x = 2(3+x)
5x + 5 - 2x = 6 + 2x
x = 6 - 5
x = 1
e. 3(x-4) - 2(3x+4) = 4(3-x) + 5x + 4
3x - 12 - 6x - 8 = 12 - 4x + 5x + 4
3x - 6x + 4x - 5x = 12 + 8 + 12 + 4
-4x = 36
x = -9
f. (1/2) (2- 6 x) - 4 ( x + (3/2)) = -(x-3) + 4
(2-6x) - 8 (x+ (3/2)) = -2(x-3) + 8
2-6x - 8x - 12 = -2x + 6 + 8
12x = 2-12 + 6 + 8
12x = 4
x = 1/3
Applications
3. a. Let equation equal target number of tiles (150)
12b + 38 = 150
12b = 150 - 38
b = (150-38)/12
b = 9.33 -> Round up to b = 10
We need to round up our answer because the supplier does not sell bundles smaller than one full bundle. Hence, 10 is the minimum number we can buy. We will thus be left with 158 tiles.
b. After buying 10 bundles and selling 150 tiles, the tile warehouse store will be left with x = 158 - 150 = 8 tiles. If the store wants to keep 30 tiles in stock at all times, it has to buy 3 more bundles of tiles. This will allow it to have 30+ 8 = 38 tiles, which exceeds the minimum required stock of 30 tiles.
Reasoning
4. Erroneous solution:
-2(x-3) = 4
5
5 . -2(x-3) = 4 . 5
5
-2(x-3) = 20
-2x - 6 = 20 ERROR: should be -2x + 6 = 20
-2x - 6 + 6 = 20 + 6
- 2x = 26
x = -13
Corrected solution:
-2(x-3) = 4
5
5 . -2(x-3) = 4 . 5
5
-2(x-3) = 20
-2x + 6 = 20
-2x = 20 - 6
- 2x = 14
x = - 7
204CCAlg1U2L5LinearWordProblems
LINEAR WORD PROBLEMS COMMON CORE ALGEBRA I
Exercise #1:
(a)Test a: 1
1 + 5 = 6 (wrong number)
Test b: 2
2 + 5 = 7 (wrong number)
Test c: 8
8 + 5 = 13 (wrong number)
(b):Let the number of interest be x
x + 5 = 17
x = 17 - 5 = 12
The number is 12.
Exercise #2:
(1) 2n - n + 5 = 3
(2) n - (2n + 5) = 3
(3) n + 5 - 2n = 3
(4) 2n - (n+5) = 3
The option (4) could be used the find the value of the number, n, because its first term (2n) and its second term (n+5) correspond to those of twice the number and a number that is five more than it is. Furthermore, the equation takes the difference between the two.
As proof:
2n - (n+5) = 3
n - 5 = 3
n = 8
The number is 8.
Exercise #3
(a) Test 1: Let us say Evie’s age is 5.
Now: Evie’s father is 36 + 5 = 41
3 years from now: Evie’s father should be 44, but five times her age (8) is 40.
This number is wrong.
Test 2: Let us say Evie’s age is 10.
Now: Evie’s father is 36 + 10 = 46
3 years from now: Evie’s father should be 49, but five times her age (10) is 50.
XXXX number is XXXXX.
(b) XXX Evie’s age now XX x, XXX her father’s age at current time be x + XX.
XXX Evie’s age three XXXXX from XXX XX x + X, and her father’s age X XXXXX from now XX XX + 15, or also, x + XX + 3 = x + XX
Three years XXXX now: her father’s age XX XXXXX XX:
XX + XX = x + 39
4x = 24
x = 6
Hence, XXXX XX 6 years old XXX.
XXXXXXXX #4
Kirk = x, Jim = y
XXXXXXXX 1: x + 12 = y
XXXXXXXX 2: (X/X) y = x - 2
XXX XXXXXXXX 2 be transformed XXXX EQUATION X (XXXXXXXX XXXX XXXXX XX X): y = XX - X
XXXXXXXXX, equating XXXXXXXX 1 XXX EQUATION X:
x + XX = XX - X
x = 16
y = x + 12 = XX + XX = 28
XXXX XXX 16 dollars, XXX XXX 28 dollars
XXXXXXX
X. (X) XXX first XXXXXXXX, XX + (XX -2) = 15 , could XX used to XXXX XXX value XX XXX number n. XXXX XX XXXXXXX the XXXXX equation contains XXX XXX XX three times a XXXXXX XXX X XXXX than X XXXXX that same number, XXX XXXXX their XXX XXX XXXXXXX it to the XXXXXX number XX XX.
X.
- Let XXX XXX XX 3 XXXX XXXX X XXXXX a number XXX the number increased XX X equalling 24 be:
XX - X + (x+9) = 24
XXXXXXX the equation:
XX + X = 24
x = 18/X = 3
(b) Let XXX’s age XX t, Andrew’s age XX a, Sara’s age XX s. The equations XXX as XXXXXXX:
t = XX + X
s = 5a - X
t = s because XXX and Sara XXX twins.
2a + 4 = XX - 8
3a = XX
a = X
t= X(4) + 4 = XX
s = 20 - X = 12
XXXXXX is 4 years XXX.
(c) XXXXX months of use = x, x=X and XXXX XX plan is XXXXX XX $XX(x) + $12.XX = $XX.XX, XXX total texts are 450, cost XXX XXXX XX XX.5/XXX = $0.105.
(d) XXXXXX’s XXX’s age XX x, XXXXXX’s age is x + XX. XX six years, XXXXXX ’s son will be x+6, XXXXXX will XX 3(x+X) or x + 26 + 6 = x + XX.
XXXXX, let XXXXXX’s age in 6 years XX either X(x+X) or x + XX.
Equating both XXXXXXXXXXXXX XXX XXXXXX’s age in 6 years, we get:
3(x+6) = x + XX
XX + 18 = x + XX
3x - x = XX
XX = XX
XXXXXX’s son’s XXXXXXX age: x = 7 XXXXXX’s XXXXXXX age: x + XX = 33
XXXXXXXXX, XXXXXX’s son XX 7 XXX Daniel is 33.
XXXXXXXXXXXX
3. XXX age XX manager be x, XXXX XX 2(x-XX), Brian be XX - XX, Matt be 0.XX + 6
The XXXXX of their ages is given by the equation:
x + 2(x - 10) + 2x - 12 + X.XX + X = 106
x + XX - 20 + XX - XX + 0.5x + X = 106
X.XX = XXX
x = 24 (Therefore, manager is 24)
Kirk is X(XX-10) = XX XXXXX XXX.
XXXXX XX X(24) - XX = XX years old.
Matt is 0.X(XX) + X = 18 years XXX.
XXXXXXXXX
XXX 0.15x+25 = 0.XXX + XX.X
0.05x = -X.5
x = -130
XXXXX XXX XXXXXXX, XXX two plans will XXXXXX the same amount.
XXXX XXXXX that XXXXXXX’s plan XX XXXXXXXXX more XXXXXXXXX XXXX XXXXXXX’s plan.
428CCAlg1U2L2SeeingStructuretoSolveEquations
XXXXXX STRUCTURE TO SOLVE XXXXXXXXX XXXXXX CORE XXXXXXX I
XXXXXXXX #X
- x was multiplied XX X and increased XX 3, and XXXX XXX XXXXXX XXXX XXXX XXXX XX XXX equation XXX XXXXXXX XX 23.
- XX + X = XX
5x = XX - X
XX = XX
x = 4
XXXXXXXX #2
(a) What happened to x? x was reduced by 3, divided by X and X was added XX the entire sum. XX XXX then equated XX -X.
x - 3 + X = 23
2
x - 3 + 14 = 46
x = 46 - 14 + X
x = XX
(b) What XXXXXXXX XX x? x was XXXXXXXXX XX X, x+1 XXX multiplied by 4, XXX the whole sum was XXXXXXX by X. XX was then XXXXXXX to -6.
X(x+X) - X = -6
4x + X - X = -6
XX = -6 + 2 - X
XX = -X
x = -2
Exercise #X
(a) -2 (x - 4) + 8 = X
-2(x-4) + X = 0
-X (x-X) = -6
(x-X) = X
x = 4+X
x = 7
(b) XXXXXXXXXXXX XXXXXXXX
-X (x - X) + X = 2
-2x + 8 + X = X
-2x = -XX
x = -14/-2
x = 7
XXXXXXXX #X
(a) Setting up XXX XXXXXXXX: XX - 10 = 35
XX = XX
x = X
XXXXXXXXXXXX x = 5 XXXX the original equation
X (9) - XX = 35
span class="Apple-converted-XXXXX"&XX;
(b) XXXXXXX up XXX equation: (X(x+X)) + 10 = X
XXXXX XXX distribution method:
XX + 21 + 10 = X
3x = X- XX - XX
XX = - XX
x = -X
XXXXXXX
X. x/X - 3 XX comprised of x divided XX X, and XXXXXXX (subtracted) by 3.
Hence, XXX correct XXXXXX XX (X).
2. 6x + X = X
6x = X - 1
XX = 3
x = X/X = 1/X
The answer XX (X)
X. X(x-X) - X = 24
X(x-2) = 24 + X
5x - XX = XX
XX = 40
x = XX/5 = 8
The correct answer is (X)
XXXXXXXXXXXX
4.
(x + X) = 7
X
x + X = XX
x = XX - 5
x = 16
5. XX the XXXXXXX, let Max’s age XX m, Zeke’s age be X.
XXX XX set XX XXX XXXXXXXX.
2(m-3) + X = XX
X = 8
Substituting z = X
2 (m - X) + X = XX
XX - 6 + 8 = 26
XX = XX + X - X
XX = XX
m = XX
XXX answer is XXXXXXX because m - 3 = X, XX XXXXXX it XX XX, XXX to add it XX 8 is 26.
The XXXXXXXX holds.
6. (a) F = 2W + XX
(b) F = XX + 2L
F = 2(XX) + X(XX)
X = XX
(c) If X = XXX, XXX X = 30, then:
120 = XX + X(XX)
2W = 60
X. (a) x was multiplied by X, the result XXX reduced XX 1, the result was multiplied XX 5, the XXXXXX XXX divided by 3, the result XXX XXXXXXX XX 4, XXX result was equated XX XX.
(b) 5 (2x - 1) - 4 = XX
X
XXXXXXXX XXXXXXXXXX by 3, expand left hand side XX XXX XXXXXXXX
XXX - X - XX = XX
10x = XX
x = XX/XX
x = 5
X. (a) x was multiplied XX 3, the XXXXXX was XXXXX XX X, the XXXXXX was multiplied XX X, the XXXXXX was equated to -XX.
4(3x + 2) = -16
XX + 2 = -64
3x = -66
x = -22
(b) X(3x + X) = -16
XXX + X = -XX
12x = -24
x = -X
464CCAlg1U2L8Inequalities
INEQUALITIES (JUST XXXXXXX TRUE/FALSE QUESTION) COMMON XXXX ALGEBRA I
Exercise #X
- XXXX (b) True (c) XXXXX (d) XXXX (e) True (f) True (g) False (h) XXXX
Exercise #2
span class="Apple-XXXXXXXXX-XXXXX"&XX;
- True
-4 -3 -X -1 X X X X
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
(b) False
-5 -X -X
XXXXXXXXXXXXXXX
(c) XXXX
-6 -5 -X -3 -2 -1 0
________________________________________
XXXXXXXX #4
X(x - 2) ≥ 2x + X
(a) X(XX - 2) ≥ X (XX) + X
XX ≥ 20 + X
XX ≥ 21
XXX inequality XX XXXXX
(b) X(X - 2) ≥ X (5) + X
X ≥ XX
XXX inequality is XXXXX
(c) 3(X - 2) ≥ X (X) + X
-X ≥ X
XXX inequality is XXXXX
(d) 3(X - 2) ≥ X (X) + 1
XX ≥ XX
XXX XXXXXXXXXX XX true
Exercise #5
(a) 2x + 4 &XX; 4x - 1
x = 1
2(X) + 4 &XX; X(1) - X
X > 3
The XXXXXXXXXX is true
(b) -3 (x+X) ≥ x+7
X for x = -X
-6 (x + 5) ≥ x + X
-X (-3 + 5) ≥ -3 + X
-XX ≥ X
XXX inequality is XXXXX
(c) x2 -10x + X &XX; XX + 5x XXX x = -X
XXXXXXXXXX x = -2
(-X)
4 + 20 + X &XX; 20 - XX
XX < 10
The inequality is false
(d) 2 (x - 5) + X ≤ x - X XXX x = 5
X X
X (X - X) + 1 ≤ X - X for x = X
X X
X + 1 ≤ 1/3
X ≤ 1/3
span XXXXX="XXXXX-converted-XXXXX"&XX;
INEQUALITIES XXXXXX XXXX XXXXXXX I HOMEWORK
XXXXXXX
- (a) XXXX (b) XXXXX (c) XXXXX (d) XXXX (e) XXXXX (f) True (g)True (h) False
X. (a) XX + 2 ≤ XX - 5 XXX x = 8
X(8) + X ≤ X(8) - 5
XX + 2 ≤ XX - 5
XX ≤ 11
The inequality XX false
(b) XX + X ≤ 2 - 3x XXX x = -2
3(-2) + X ≤ X - 3(-2)
-X + X ≤ -X
XXX inequality is XXXX
(c) (x-3)
(3-3)
0 > -XX
XXX inequality XX true
(d) X (3-2x) ≤ XX - X(x+X) XXX x = -X
5
2 (3+2) ≤ -2 - 3(0) XXX x = -1
5
12/X ≤ -2
The inequality is XXXXX
(e) 3
6 X XXX x = 3
X - 12 + X &XX; X + 1
X 5 for x = 3
X &XX; XX
6 5 for x = X
X > X for x = X
XXX inequality is false
| -2 (X - x) | ≥ XX - X
3 X for x = -X
| -X (5 +X) | ≥ -X - X
X 2 XXX x = -X
X ≥ -2
The XXXXXXXXXX XX XXXX
Applications
X.
x = XX
3(x + 5) - 1 + 4 (2x - X) ≤ 125
2
3(XX + X) - X + 4 (2(XX) - 3) ≤ 125
2
XX/2 + 84 ≤ XXX
XXX ≤ XXX
XXX XXXXXXXXXX is XXXX. The XXXXXXX is XXXX XX XXX XX pressure = 12
x = XX
3(x + X) - X + 4 (2x - X) ≤ XXX
X
3(XX + 5) - 1 + X (X(XX) - 3) ≤ 125
2
XX/X + XX ≤ XXX
118.X ≤ XXX
The XXXXXXXXXX is true. XXX XXXXXXX XX XXXX XX XXX XX pressure = 13
x = XX
3(x + X) - 1 + 4 (2x - 3) ≤ 125
X
3(14 + 5) - X + 4 (2(XX) - X) ≤ 125
X
XX + XXX ≤ XXX
128 ≤ XXX
The inequality XX false. XXX XXXXXXX is unsafe XX XXX at pressure = 14
(b) x = X
3(x + X) - X + X (XX - X) &XX; XX
2
X(X + X) - 1 + X (2(X) - 3) > 35
X
14.X + 28 &XX; XX
XX.5 &XX; XX
span XXXXX="Apple-XXXXXXXXX-space"&XX;
XXXXXXXXX
X. (a) X(-X) + 2 &XX; 1 - 3(-X)
-6 < 7
span XXXXX="XXXXX-XXXXXXXXX-space"&XX;
(b) (2x + 1)/ (-3) < 4 / (2-XX)
(X(-2) + X)/ (-3) > X / (X-X(-X))
X &XX; 4/X
1 &XX; 1/X
XXX correct sign XX &XX;
(c) 2x
2(4)
XX > XX
The correct XXXX is >
(d) ((3(2x - 5)) / 3) + 2 &XX; X(X(x) - 6)
((3(2(X) - X)) / X) + 2 &XX; X(X(X) - X)
X < 72
XXX XXXXXXX sign XX <
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
EQUATIONS XXX XXXXX XXXXXXXXX COMMON CORE XXXXXXX I
XXXXXXXX #X
(3) X(XX + 1) XX not an XXXXXXXX.
XXX XXXXX three options are XXXXXXXXX XX they XXX in XXX XXXXXXXX format.
Exercise #2
(a) We cannot determine XXXXXXX XX - 8 = XX - x is true or false as we XX XXX know XXX XXXXX of the unknowns, and hence we XX not know XX the XXXXXXXX holds.
(b) If x = 5, the XXXXXXXX evaluates to 10 - X = 10 - 5 &XX;>> 2 = X. The equation will be XXXXX.
(c) XX - 8 = 10 - x
X(6) - 8 = XX - X
X = 4
span class="XXXXX-XXXXXXXXX-XXXXX"&XX;
Exercise #X
(a) 2x + X = 17
X(X) + X = 17
17 = XX
The equation is true.
(b) (x - 20) = -4
X
(10 - 20) = -X
5
(-10) = -4
5
-2 = -X
The XXXXXXXX is XXXXX
(c) 2 (x+X) = 6 (x - 1)
2 (4 + 5) = 6 ( 4 - 1)
XX = XX
The equation XX true
(d)
x
(-X)
X -X = 2 - 2
0 = 0
The XXXXXXXX XX XXXX
(e) 3 (x + 2) - X = X
4
3 ((2) + 2) - 1 = 5
X
12 - 4 = XX
X = XX
XXX XXXXXXXX XX XXXXX
(f) 3/4 x - X = -1/2 x + X
3/X (X) - X = -1/X (8) + 9
6 - 1 = X - X
X = X
The XXXXXXXX is XXXX
Exercise #X
XX - 3 = X x + 11
X(7) - 3 = 2(7) + XX
XX = 25
XX XX correct XX a solution.
Kirk’s XXXXX was to complete XXX operations 7-X XXX X + XX before the XXXXXXXXXX 4(X) and X(7).
Multiplication should always XXXX before XXXXXXXX and XXXXXXXXXXX.
XXXXXXX
X. (a) XXXXXXXXXX (b) XXXXXXXX (c) Equation (d) Expression (e) Expression (f) Equation
2. (a) x - X = XX
X - 4 = 12
X = 12
(b) (X+x) / 4 = X
(X+X) / X = 3
XX/4 = 3
XXX equation is true. The XXXXXXXX XX valid for the given equation.
(c) (x + X) - X(x-X) = X
(X + X) - 3(X-4) = X
6 - X(0) = 6
6 = X
XXX equation XX XXXX. XXX solution is XXXXX for the XXXXX XXXXXXXX.
(d) 1/X (x+2) = - X/5 (x-9)
1/3 (X+X) = - 2/5 (4-9)
X = X
The XXXXXXXX XX XXXX. The XXXXXXXX is XXXXX XXX XXX XXXXX equation.
Applications
3.
Day X: P = 6(1) + X = 11
Day 2: X = 6(2) + 5 = 17
XXX X: X = X(X) + 5 = XX
XXX 4: P = X(4) + X = 29
Day 5: X = 6(5) + X = XX
Day X: X = 6(X) + X = 41
XXX X: X = 6(7) + 5 = 47
XXX 8: P = X(X) + 5 = XX
We will observe XXXXX X on XXX X, Stage 2 XX Day 2 to 3, XXXXX X XXX XXX 4 XX 7, and XXXXXXXXX state XX XXX 8.
XXXXXXXXX
4. XXX + 30 = 250
(a) Savings XXXXX 9 XXXXX = XX (X) + XX = 255
Yes, bobby will XXXX XXXXXX as XXX &XX; 250
(b) 25w + 30 + 10w = 250 + XXX
After X weeks of XXXXXX = 25(9) + XX + XX(9) = 345
XXXXX needs XXX + 100 = 350
Nine XXXXX is XXX XXXXXX XXXX XXX Bobby XX save XX XXX &XX; XXX
527CCAlg1U2L9SolvingLinearInequalities
SOLVING XXXXXX INEQUALITIES COMMON CORE ALGEBRA I
Exercise #X
(a) XXX XXX XXXXXXXXXX is X < 11. XXXX is a true XXXXXXXXXX.
(b) XXX XXX XXXXXXXXXX is X &XX; X. This XX a XXXX inequality.
(c) XXX new inequality is X < XX. This XX a true XXXXXXXXXX.
(d) The XXX XXXXXXXXXX XX 2 &XX; 4. This is a true XXXXXXXXXX.
Exercise #X
(a) XXX XXX XXXXXXXXXX XX -X < -16. This XX a false inequality.
(a) The new inequality XX -2 < -X. This XX a XXXXX inequality.
Exercise #3
(a) The XXXXXXXXXX is 5 &XX; 8. When XXXXXXXXXX XX -4, it becomes -20 < -32. XXXX becomes XXXXX.
XXXXXXXX #X
(a) XX - 3 ≥ 5
4x ≥ 8
x ≥ X
(b) / (c)
XXX five numbers XXX 3, 4, X, X, X
The XXXXXXXX is indicated XX the XXXXX >&XX;>>&XX;&XX;&XX;&XX;&XX;
>&XX;&XX;>>>&XX;>&XX;&XX;&XX;&XX;>>&XX;>>&XX;&XX;&XX;>>&XX;>>&XX;>>&XX;>&XX;>
-XX -9 -X -7 -6 -X -4 -X -2 -1 0 X X 3 X X 6 7 8 9 XX
|____|____|XXXX|XXXX|XXXX|____|____|XXXX|XXXX|____|XXXX|XXXX|____|XXXX|XXXX|XXXX|XXXX|XXXX|____|____|
XXXXXXXX #5
(a) XXXXXXX the left hand expression XX an equivalent XXXXXXXXXX using XXXXXXXX.
8 - 2x > XX
X - XX > 2x
(b) XXXXX XXX XXXXXXXXXX
8 - XX > 16
8 - XX > 2x
-X &XX; XX
-X &XX; x
x < -4
(c) XXX x = -X
XX -6 < -4, XXX original inequality XX true
(d)
XXX XXXXXXXX is indicated by the XXXXX >&XX;&XX;&XX;&XX;>>>>
<&XX;<&XX;&XX;<<&XX;&XX;<<<<<<&XX;<&XX;<<<<<
-XX -9 -X -7 -6 -5 -X -X -X -X X 1 X X 4 X 6 X X 9 10
|XXXX|XXXX|XXXX|XXXX|XXXX|XXXX|____|XXXX|XXXX|XXXX|XXXX|XXXX|XXXX|____|____|XXXX|____|____|XXXX|XXXX|
Exercise #6
(a)
X (x-2) - 3 (2x + 1) ≤ XX + X - 3(x+X)
XX - 16 - XX - X ≤ XX + 4 - XX - X
2x - 19 ≤ XX + X
-XX ≤ 20
(b)
X (x-X) - 3 (2x + 1) ≤ 7x + X - 3(x+1)
8x - 16 - XX - 3 ≤ XX + 4 - 3x - X
XX - XX ≤ XX + 1
-2x ≤ XX
-x ≤ 10
x ≥ -XX
O&XX;&XX;&XX;>&XX;>&XX;&XX;>&XX;>>&XX;&XX;>>>>>>>&XX;>>>&XX;>>&XX;&XX;
-16 -XX -XX- 13 -12 -XX -XX -9 -8 -7 -6 -X -X -X -X -X X
|XXXX|XXXX|XXXX|XXXX|XXXX|____|____|____|____|____||____|XXXX|XXXX|____|XXXX|____|
XXXXXXX
(a)
XX - 6 ≤ XX
XX ≤ 30
x ≤ 6
The solution XX indicated by the range >>&XX;>>>&XX;>&XX;
&XX;&XX;<&XX;<<&XX;&XX;<&XX;&XX;&XX;<<&XX;<&XX;&XX;<&XX;&XX;<&XX;<&XX;&XX;<&XX;<<&XX;&XX;&XX;<<&XX;&XX;<<&XX;&XX;&XX;<&XX;&XX;<&XX;<&XX;<<&XX;&XX;&XX;<<&XX;&XX;O
-XX -9 -X -7 -X -X -4 -X -X -X X X 2 3 4 5 X X 8 9 XX
|____|XXXX|____|____|____|XXXX|____|____|____|____|____|XXXX|____|____|XXXX|XXXX|XXXX|____|____|XXXX|
(b)
X(X-x) ≤ XX
XX - 2x ≤ 12
XX - 12 ≤ XX
-2 ≤ XX
-X ≤ x
The solution is XXXXXXXXX by XXX XXXXX &XX;>>>>&XX;&XX;&XX;>
<<<&XX;&XX;<&XX;&XX;&XX;<<<<&XX;<<&XX;<<<<&XX;<<&XX;&XX;&XX;&XX;&XX;<<<&XX;X
-10 -9 -8 -7 -X -X -4 -X -2 -X 0 X X 3 4 5 X 7 8 X 10
|XXXX|XXXX|XXXX|XXXX|XXXX|____|XXXX|XXXX|____|XXXX|XXXX|XXXX|XXXX|XXXX|XXXX|XXXX|XXXX|XXXX|____|XXXX|
(c)
X - XX &XX; 18
-XX &XX; 12
x &XX; XX/-X
x < -X
XXX solution XX indicated XX XXX XXXXX >&XX;&XX;>&XX;&XX;>>&XX;
&XX;&XX;&XX;<&XX;&XX;&XX;<<&XX;<<<<&XX;<&XX;&XX;<<<&XX;<&XX;<<<
-XX -X -8 -7 -6 -5 -4 -X -2 -1 0 1 X 3 X X 6 7 8 9 10
|XXXX|XXXX|____|____|____|XXXX|____|XXXX|XXXX|____|____|XXXX|XXXX|XXXX|XXXX|XXXX|____|____|____|____|
(d)
8x - 6(x-X) &XX; 20 - XX
XX - XX + 12 &XX; 20 - 2x
XX + XX &XX; XX - 2x
XX &XX; XX - 12
4x > X
x &XX; 2
&XX;>>>&XX;>>>&XX;&XX;>>>&XX;>&XX;>&XX;&XX;>&XX;&XX;&XX;&XX;>>
-10 -X -X -7 -X -5 -4 -3 -X -X 0 X 2 X X X X 7 8 9 10
|XXXX|XXXX|____|____|XXXX|____|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|XXXX|____|____|____|XXXX|XXXX|XXXX|
(e)
X (XX + 2) > 1 x + 2
6 X
X (2x + X) > 2x + XX
XX + X > XX + XX
XX > 6
x > 1.X
&XX;>>>&XX;&XX;>>>&XX;>&XX;>&XX;&XX;&XX;>&XX;&XX;&XX;&XX;>&XX;&XX;&XX;>&XX;
-XX -X -8 -X -X -5 -X -3 -2 -X X X X 3 4 5 6 7 X X 10
|XXXX|XXXX|XXXX|XXXX|XXXX|____|____|____|XXXX|____|____|XXXX|XXXX|____|____|XXXX|____|____|XXXX|XXXX|
Applications
X. (a)
XXXXX will pay XX + 5.25n
Edwin will XXX XXXX than Rhea if:
XX + X.XXX &XX; XXX
Solving the XXXXXXXXXX:
X.25n > XXX - XX
X.25n &XX; XX
n > XX
(b)
Edwin XXX take 11 XXXXX XXX XXXXX pay XXXX XXXX XXXX. XXXX XX XXXXXXX XX XXXX XXXX them XXXXX, XXX XX or XXXXX XXXX XXXX Edwin XX XXX XXXX than XXXX.
XXXXXXXXX
3. (a) XX + b ≥ XX
ax ≥ cd - b
x ≥ (XX - b) / a
(b)
a (x + 2) &XX; c
b
XX + 2a &XX; XX
x &XX; XX - XX
a
4. The XXXXXXX answer XX (X)
XX + b > d
x > (d - b) /a
≥ ≤
XXXXX
Document X: Modern XXX XXXXXXXXXXXXXXX/Dictatorship: X XXXXX XX XXXXX Korea
What historical XXXXXXX XXX you provide XX XXX North Korean XXXXXXXXXX XXXX XX XXXXXXXXXX with XXX XXXXXXXX XXXXX you chose?
span XXXXX="XXXXX-converted-XXXXX">
XXXXX Korea was formed out XX the repressive government of Kim Il-Sung, a post-XXX nationalist XXXXXXXXX XXX XXXXXXXXX XXX XXXXX XXXXXXXXX of XXX North Korean XXXXXX in order to XXXX with national emergencies such as XXX Korean XXX. Furthermore, Kim XX-Sung XXX XXX descendants XXXX XXXXXXXXX to consolidate power in a way XXXX curtails human rights in XXXXX XXXXX. They have created a XXXXXX XXXXX XXXX speech XX disallowed, and XXXXX XXXXXXXX penalties XXXXXXXXX abuse XXXXX rights. XXXXX XXXXXXX the XXX XX XXXXXXX, XXXXXX labor XXX XXXXXXXXXXXXX in XXXXXXXX conditions. There XX also no XXXXXXXXXXX XXX process XXXXXX XXX judicial system. XXX lack of XXXXX rights in XXXXX XXXXX XX a XXXXXX of XXXXXXX of XXXXXXXXXXXXX by the North Korean XXXXXXXXX dictatorship, in a bid XX XXXXXXXX XXXXX firm XXXX XX power over XXX country.
XXX XXXX the issue XX power/human rights in XXX government of North XXXXX XXXXXX XXXXXX?
span class="XXXXX-converted-XXXXX"&XX;
94233
Regular equations
1a. x - X = 8
x = X + 7
x = 15
XX. x - b = a
x = a + b
2a. 4x = -XX
x = -X
XX. -XX = m
X = m/(-3)
k = -X m
3
3a. XX - 5 = 11
x = (11 + X)/2 = 8
3b. 2b - X = d
b = (d + X) / X
XX. X/X (XX) = -XX
4x = -40
x = -XX
XX. XXX = 10
g = 10 / XX
XX. x / -X = XX
x = - 88
5b. y/3 = h
y = 3h
70852
XXXXXXXX 4: XXXXXX Day XXXXXXXXXXXXXXX/XXXXXXXXXXXX: A Study of North Korea
What historical XXXXXXX can you XXXXXXX XX XXX XXXXX XXXXXX XXXXXXXXXX that is associated with XXX XXXXXXXX issue you XXXXX?
span XXXXX="XXXXX-XXXXXXXXX-XXXXX"&XX;
XXXXX Korea was formed out of the XXXXXXXXXX XXXXXXXXXX XX Kim XX-Sung, a XXXX-war nationalist communist who suspended XXX XXXXX liberties of the North XXXXXX people in order to deal with XXXXXXXX XXXXXXXXXXX such XX XXX Korean XXX. XXXXXXXXXXX, XXX XX-XXXX and XXX descendants XXXX XXXXXXXXX to XXXXXXXXXXX XXXXX in a XXX that curtails human rights in XXXXX Korea. They have XXXXXXX a regime XXXXX free speech XX XXXXXXXXXX, XXX XXXXX judicial penalties routinely XXXXX human XXXXXX. These include the XXX XX XXXXXXX, XXXXXX XXXXX XXX incarceration in XXXXXXXX XXXXXXXXXX. XXXXX XX also no XXXXXXXXXXX XXX XXXXXXX XXXXXX the XXXXXXXX XXXXXX. The lack XX XXXXX XXXXXX in XXXXX XXXXX is a XXXXXX of XXXXXXX XX XXXXXXXXXXXXX XX the North Korean XXXXXXXXX dictatorship, in a XXX to continue their XXXX grip XX power XXXX XXX XXXXXXX.
XXX does XXX issue XX power/XXXXX XXXXXX in XXX XXXXXXXXXX XX North XXXXX XXXXXX XXXXXX?
span class="Apple-converted-XXXXX"&XX;
XXXXX
Unit 2 Exam
X. 1.
X. X.
9. 2.
XX. 4.
XXXXX
XXXXXXX XXXXXXXXX: Worksheet #1
6a.
XX = 2x + XX
XX = XX - 14
x = XX / X
x = 6
XX. XX = XX + X
XX = XX - X
v = (XX - X) /X
7a. -30 = X - XX
8x = X + XX
x = XX/8
XX. 7a = 10 - XX
2h = 10 - 7a
h = (XX - XX) /2
XX. X(x-X) = 12
XX - 12 = XX
XX = XX
x = 8
XX. 5(4x + p) = w
20x + 5p = w
5p = w - 20x
p = (w - XXX) / 5
XXXXX XX XXXXXXXXXX XX 7a - 8b = XXX
a = (XXX + XX) / 7
The answer XX X
XXXXX is XXXXXXXXXX XX XXX + k = 13
k = XX - XXX
The XXXXXX is C