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A. x/3 - 7 = -2 x/3 = 5 x = 15 |
B. 4x + 3 = -17 4x = -20 x = -5 |
C. 5x + 12 = 87 x = (87 - 12)/5 x = 15 |
D. (x+7)/3 = 2 x+7 = 6 x = -1 |
E. -6 (x-1) = 18 -6 = 18x - 18 18x = 12 x = 12/18 x = 2/3 = 0.66 |
F 8x + 2 = -2 8x = -2 -2 x = -1/2 = -0.5 |
G (3/4)x - 5 = 4 (3/4)x = 9 x = 9 * (4/3) x = 12 |
H (-5/2)x + 6 = 1 (-5/2)x = -5 x = (-5)/(-5/2) x = 2 |
I 6x + 3 = -1 6x = -4 x = -(4/6) = -(2/3) = -0.66 |
Exercise #2
5(x-3) + 2 = 7
8
5(x-3) + 16 = 56
5(x-3) = 40
x-3= 8
x = 11
Exercise #3
(a) 5(x-3) + 2x = 4(x+3)
5x - 15 + 2x = 4x + 12
7x - 15 = 4x + 12
(b) 7x - 15 = 4x + 12
3x = 27
x = 9
Let x = 9 for 5(x-3) + 2x = 4(x+3)
5(9-3) + 2(9) = 4((9)+3)
30 + 18 = 48
The equation holds true.
Exercise #4
(a) 7(x-2)-3(x+3) = 5(x-3) + x
7x - 14 - 3x - 9 = 5x - 15 + x
4x - 23 = 6x - 15
2x = -8
x = -4
(b) 9 - 6(x+1) = 2(x-4) + 27
9 - 6x - 6 = 2x - 8 + 27
3 - 6x = 2x + 19
8x = 3-19
x = (-16)/8
x = -2
Fluency
1.
a. 7x - 15 = 1
7x = 16
x = 16/7 = 2.28
b. (x+2)/4 = -2
x+2 = -8
x = -10
c. (-3/5)x + 2 = 7
(-3/5)x = 5
x = -8.333 OR -8 and 1/3
2.
a. 5(x+1) + 4 = 4
6
5(x+1) + 4 = 24
5x + 9 = 24
5x = 15
x = 3
b. 5(x-3) + 2 = 7
8
5(x-3) + 16 = 56
5x - 15 + 16 = 56
5x + 1 = 56
5x = 55
x = 11
c. -(3/2)x + 2 = -4
-(3/2)x = -6
(3/2)x = 6
x = 4
d. 5(x+1) - 2x = 2(3+x)
5x + 5 - 2x = 6 + 2x
x = 6 - 5
x = 1
e. 3(x-4) - 2(3x+4) = 4(3-x) + 5x + 4
3x - 12 - 6x - 8 = 12 - 4x + 5x + 4
3x - 6x + 4x - 5x = 12 + 8 + 12 + 4
-4x = 36
x = -9
f. (1/2) (2- 6 x) - 4 ( x + (3/2)) = -(x-3) + 4
(2-6x) - 8 (x+ (3/2)) = -2(x-3) + 8
2-6x - 8x - 12 = -2x + 6 + 8
12x = 2-12 + 6 + 8
12x = 4
x = 1/3
Applications
3. a. Let equation equal target number of tiles (150)
12b + 38 = 150
12b = 150 - 38
b = (150-38)/12
b = 9.33 -> Round up to b = 10
We need to round up our answer because the supplier does not sell bundles smaller than one full bundle. Hence, 10 is the minimum number we can buy. We will thus be left with 158 tiles.
b. After buying 10 bundles and selling 150 tiles, the tile warehouse store will be left with x = 158 - 150 = 8 tiles. If the store wants to keep 30 tiles in stock at all times, it has to buy 3 more bundles of tiles. This will allow it to have 30+ 8 = 38 tiles, which exceeds the minimum required stock of 30 tiles.
Reasoning
4. Erroneous solution:
-2(x-3) = 4
5
5 . -2(x-3) = 4 . 5
5
-2(x-3) = 20
-2x - 6 = 20 ERROR: should be -2x + 6 = 20
-2x - 6 + 6 = 20 + 6
- 2x = 26
x = -13
Corrected solution:
-2(x-3) = 4
5
5 . -2(x-3) = 4 . 5
5
-2(x-3) = 20
-2x + 6 = 20
-2x = 20 - 6
- 2x = 14
x = - 7
204CCAlg1U2L5LinearWordProblems
LINEAR WORD PROBLEMS COMMON CORE ALGEBRA I
Exercise #1:
(a)Test a: 1
1 + 5 = 6 (wrong number)
Test b: 2
2 + 5 = 7 (wrong number)
Test c: 8
8 + 5 = 13 (wrong number)
(b):Let the number of interest be x
x + 5 = 17
x = 17 - 5 = 12
The number is 12.
Exercise #2:
(1) 2n - n + 5 = 3
(2) n - (2n + 5) = 3
(3) n + 5 - 2n = 3
(4) 2n - (n+5) = 3
The option (4) could be used the find the value of the number, n, because its first term (2n) and its second term (n+5) correspond to those of twice the number and a number that is five more than it is. Furthermore, the equation takes the difference between the two.
As proof:
2n - (n+5) = 3
n - 5 = 3
n = 8
The number is 8.
Exercise #3
(a) Test 1: Let us say Evie’s age is 5.
Now: Evie’s father is 36 + 5 = 41
3 years from now: Evie’s father should be 44, but five times her age (8) is 40.
This number is wrong.
Test 2: Let us say Evie’s age is 10.
Now: Evie’s father is 36 + 10 = 46
3 years from now: Evie’s father should be 49, but five times her age (10) is 50.
This XXXXXX is XXXXX.
(b) Let Evie’s age now be x, and her XXXXXX’s age XX XXXXXXX XXXX be x + XX.
Let Evie’s age three XXXXX from now XX x + X, and her XXXXXX’s age 3 XXXXX from XXX XX 5x + 15, or also, x + XX + X = x + XX
Three years from XXX: her XXXXXX’s age is XXXXX XX:
5x + XX = x + 39
4x = XX
x = 6
Hence, XXXX XX X XXXXX old now.
XXXXXXXX #X
Kirk = x, XXX = y
XXXXXXXX 1: x + XX = y
EQUATION X: (1/2) y = x - 2
Let XXXXXXXX 2 XX XXXXXXXXXXX XXXX EQUATION X (multiply both sides XX X): y = 2x - X
XXXXXXXXX, equating XXXXXXXX 1 XXX XXXXXXXX 3:
x + 12 = 2x - 4
x = 16
y = x + 12 = XX + XX = 28
XXXX has 16 XXXXXXX, XXX has XX XXXXXXX
FLUENCY
X. (X) The XXXXX equation, XX + (XX -X) = 15 , could be used to find the XXXXX of XXX XXXXXX n. XXXX XX XXXXXXX XXX first XXXXXXXX contains XXX XXX of XXXXX XXXXX a XXXXXX XXX 2 XXXX XXXX X times that XXXX XXXXXX, XXX XXXXX XXXXX sum and XXXXXXX it to the target XXXXXX of XX.
X.
- XXX the XXX of 3 less than 5 times a XXXXXX and the XXXXXX XXXXXXXXX XX X XXXXXXXXX 24 XX:
5x - 3 + (x+9) = 24
XXXXXXX XXX equation:
6x + X = XX
x = XX/6 = 3
(b) Let Tom’s age XX t, Andrew’s age be a, XXXX’s age XX s. XXX equations XXX XX XXXXXXX:
t = XX + X
s = XX - X
t = s XXXXXXX XXX XXX Sara are XXXXX.
2a + X = XX - X
3a = 12
a = X
t= 2(4) + 4 = XX
s = 20 - X = 12
XXXXXX is X XXXXX old.
(c) XXXXX months XX use = x, x=X and XXXX XX XXXX XX XXXXX XX $35(x) + $XX.50 = $XX.XX, XXX total texts are XXX, cost XXX text is XX.5/450 = $X.XXX.
(d) Daniel’s son’s age is x, XXXXXX’s age is x + XX. In six XXXXX, Daniel ’s XXX will XX x+X, XXXXXX will be X(x+X) or x + 26 + 6 = x + XX.
Hence, let Daniel’s age in X XXXXX be either X(x+6) or x + 32.
Equating XXXX XXXXXXXXXXXXX for XXXXXX’s age in 6 XXXXX, we XXX:
3(x+6) = x + 32
XX + XX = x + XX
3x - x = XX
2x = XX
Daniel’s son’s present age: x = 7 XXXXXX’s XXXXXXX age: x + 26 = 33
XXXXXXXXX, Daniel’s son XX 7 XXX Daniel XX 33.
XXXXXXXXXXXX
X. XXX age XX XXXXXXX XX x, XXXX be X(x-XX), XXXXX be XX - 12, XXXX be 0.XX + 6
XXX XXXXX XX XXXXX ages is given by the XXXXXXXX:
x + 2(x - XX) + 2x - XX + X.XX + X = XXX
x + XX - XX + 2x - XX + 0.XX + X = 106
X.XX = 132
x = 24 (XXXXXXXXX, manager XX 24)
Kirk XX X(XX-10) = XX years XXX.
XXXXX XX X(XX) - 12 = XX years old.
XXXX is 0.5(XX) + X = 18 XXXXX XXX.
XXXXXXXXX
XXX 0.XXX+XX = 0.XXX + 18.5
0.XXX = -X.5
x = -XXX
XXXXX XXX XXXXXXX, the two XXXXX XXXX XXXXXX the same amount.
XXXX means XXXX XXXXXXX’s XXXX XX generally more XXXXXXXXX XXXX XXXXXXX’s plan.
428CCAlg1U2L2SeeingStructuretoSolveEquations
SEEING XXXXXXXXX XX XXXXX EQUATIONS XXXXXX XXXX XXXXXXX I
XXXXXXXX #X
- x was multiplied by 5 XXX XXXXXXXXX XX 3, XXX then the entire XXXX XXXX side XX the XXXXXXXX XXX equated to XX.
- XX + 3 = 23
5x = XX - X
XX = XX
x = X
Exercise #2
(a) What XXXXXXXX to x? x was XXXXXXX XX X, XXXXXXX XX X and X XXX added to the XXXXXX sum. XX was then equated XX -6.
x - X + X = XX
X
x - X + 14 = 46
x = XX - XX + 3
x = XX
(b) What happened XX x? x XXX XXXXXXXXX by X, x+1 was multiplied XX 4, and XXX whole XXX XXX XXXXXXX by 2. It XXX XXXX equated to -6.
X(x+1) - X = -6
4x + 4 - X = -X
4x = -X + X - X
4x = -8
x = -X
Exercise #X
(a) -X (x - X) + 8 = 2
-X(x-4) + 6 = 0
-X (x-X) = -X
(x-X) = 3
x = 4+X
x = 7
(b) XXXXXXXXXXXX XXXXXXXX
-X (x - X) + X = 2
-2x + 8 + 8 = X
-XX = -14
x = -14/-2
x = X
Exercise #X
(a) XXXXXXX up XXX equation: 5x - 10 = 35
5x = XX
x = 9
XXXXXXXXXXXX x = X XXXX the original XXXXXXXX
5 (9) - XX = 35
span class="Apple-XXXXXXXXX-space"&XX;
(b) Setting up the equation: (X(x+7)) + XX = 4
XXXXX XXX distribution XXXXXX:
XX + 21 + XX = 4
XX = X- XX - XX
3x = - 27
x = -9
Fluency
X. x/X - X is comprised of x XXXXXXX XX X, XXX reduced (XXXXXXXXXX) by X.
XXXXX, the XXXXXXX XXXXXX is (X).
2. 6x + X = 4
XX = 4 - X
6x = X
x = 3/X = X/2
The answer XX (X)
X. 5(x-X) - 6 = 24
X(x-2) = 24 + X
5x - 10 = 30
5x = 40
x = 40/5 = 8
The XXXXXXX XXXXXX XX (X)
XXXXXXXXXXXX
4.
(x + X) = 7
X
x + 5 = 21
x = 21 - X
x = 16
5. In the XXXXXXX, XXX XXX’s age be m, XXXX’s age XX X.
XXX us set XX XXX equation.
X(m-3) + X = 26
z = 8
Substituting z = X
2 (m - 3) + X = 26
2m - X + X = XX
2m = XX + X - 8
2m = XX
m = XX
XXX XXXXXX is correct because m - 3 = 9, to XXXXXX it XX XX, and to add it XX 8 XX 26.
The XXXXXXXX XXXXX.
X. (a) X = XX + XX
(b) F = 2W + XX
X = 2(12) + X(20)
F = XX
(c) XX X = 120, XXX X = 30, XXXX:
XXX = 2W + 2(XX)
XX = XX
X. (a) x was XXXXXXXXXX by 2, the XXXXXX XXX XXXXXXX XX X, XXX result was multiplied XX X, the XXXXXX XXX divided XX X, XXX result XXX XXXXXXX by X, XXX result was equated XX 11.
(b) X (XX - X) - 4 = 11
3
XXXXXXXX everything by X, XXXXXX XXXX hand XXXX XX XXX XXXXXXXX
XXX - X - XX = XX
10x = 50
x = XX/10
x = X
X. (a) x XXX multiplied by 3, XXX XXXXXX was XXXXX XX X, the XXXXXX was XXXXXXXXXX XX X, XXX result was XXXXXXX to -16.
X(XX + X) = -XX
3x + X = -64
XX = -66
x = -22
(b) X(3x + X) = -16
XXX + X = -XX
XXX = -24
x = -X
XXXXXXXXXXXXXXXXXXXXXXXXX
INEQUALITIES (JUST ANOTHER TRUE/XXXXX QUESTION) XXXXXX XXXX ALGEBRA I
Exercise #1
- True (b) XXXX (c) False (d) XXXX (e) True (f) True (g) XXXXX (h) True
XXXXXXXX #X
span class="XXXXX-XXXXXXXXX-space"&XX;
- XXXX
-X -3 -X -X X X 2 X
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
(b) False
-X -X -3
XXXXXXXXXXXXXXX
(c) XXXX
-6 -X -4 -3 -2 -X 0
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
XXXXXXXX #4
X(x - 2) ≥ 2x + 1
(a) X(XX - X) ≥ 2 (10) + 1
XX ≥ 20 + X
24 ≥ XX
XXX inequality is XXXXX
(b) X(X - X) ≥ 2 (X) + 1
9 ≥ 11
The inequality is false
(c) 3(X - 2) ≥ X (X) + 1
-X ≥ 3
XXX inequality is XXXXX
(d) X(X - X) ≥ 2 (X) + 1
15 ≥ 15
XXX XXXXXXXXXX XX true
Exercise #X
(a) 2x + 4 &XX; XX - 1
x = 1
X(X) + X &XX; X(X) - 1
X &XX; X
The inequality is XXXX
(b) -3 (x+5) ≥ x+X
X for x = -3
-X (x + X) ≥ x + 7
-X (-X + X) ≥ -X + 7
-12 ≥ 4
The inequality XX false
(c) x
XXXXXXXXXX x = -2
(-2)2 -XX(-2) + 1 < 20 + 5(-X)
4 + 20 + 1 &XX; 20 - 10
XX &XX; 10
The XXXXXXXXXX is false
(d) 2 (x - 5) + X ≤ x - 2 for x = 5
3 X
X (5 - X) + 1 ≤ X - X XXX x = 5
3 X
0 + X ≤ 1/3
X ≤ X/X
span class="XXXXX-converted-XXXXX"&XX;
INEQUALITIES COMMON XXXX XXXXXXX I XXXXXXXX
XXXXXXX
- (a) True (b) XXXXX (c) False (d) True (e) XXXXX (f) XXXX (g)XXXX (h) XXXXX
2. (a) 3x + X ≤ XX - X for x = 8
X(8) + 2 ≤ 2(8) - 5
24 + 2 ≤ XX - X
26 ≤ XX
The inequality XX false
(b) 3x + X ≤ X - XX for x = -X
X(-2) + X ≤ X - X(-X)
-X + X ≤ -X
The inequality is true
(c) (x-3)2 &XX; -3(x+2) XXX x = 3
(3-X)2 > -X(3+X)
X &XX; -15
The XXXXXXXXXX XX true
(d) 2 (3-2x) ≤ 2x - X(x+1) for x = -X
5
2 (X+X) ≤ -X - 3(X) XXX x = -1
5
12/5 ≤ -2
XXX XXXXXXXXXX is false
(e) 3
6 X for x = X
X - XX + X > X + X
6 5 for x = 3
6 > XX
X 5 for x = X
1 > 2 for x = X
XXX XXXXXXXXXX is false
| -X (5 - x) | ≥ 3x - X
X 2 for x = -X
| -2 (X +1) | ≥ -3 - X
3 X XXX x = -X
4 ≥ -X
XXX inequality is XXXX
Applications
3.
x = 12
X(x + X) - 1 + X (XX - X) ≤ 125
2
3(XX + X) - X + 4 (2(XX) - X) ≤ 125
2
50/X + 84 ≤ XXX
XXX ≤ XXX
The inequality is XXXX. The machine is XXXX XX XXX XX pressure = XX
x = 13
3(x + 5) - X + 4 (2x - X) ≤ 125
X
3(13 + 5) - 1 + 4 (X(XX) - 3) ≤ XXX
2
XX/X + 92 ≤ 125
118.X ≤ XXX
XXX XXXXXXXXXX XX XXXX. The XXXXXXX XX safe XX run XX pressure = XX
x = 14
X(x + X) - 1 + 4 (XX - X) ≤ 125
2
X(XX + X) - X + X (2(14) - X) ≤ XXX
X
XX + 100 ≤ XXX
128 ≤ 125
XXX XXXXXXXXXX is XXXXX. XXX machine XX unsafe XX XXX XX XXXXXXXX = 14
(b) x = X
3(x + X) - X + 4 (2x - X) &XX; XX
2
3(5 + 5) - X + X (X(5) - X) &XX; 35
X
XX.X + XX &XX; 35
XX.X &XX; 35
span class="Apple-XXXXXXXXX-XXXXX"&XX;
XXXXXXXXX
4. (a) 4(-2) + X &XX; X - 3(-X)
-X &XX; X
span XXXXX="Apple-XXXXXXXXX-XXXXX">
(b) (2x + 1)/ (-X) < 4 / (2-3x)
(X(-2) + X)/ (-X) &XX; X / (2-X(-2))
1 &XX; 4/X
1 > X/X
XXX correct sign XX &XX;
(c) 2x
2(X)X +5 > |1 - 9(4)|
37 &XX; 35
XXX correct XXXX is >
(d) ((3(2x - 5)) / 3) + 2 &XX; 8(3(x) - X)
((3(X(X) - 5)) / X) + X < X(X(X) - 6)
7 < 72
The XXXXXXX XXXX XX <
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
EQUATIONS AND XXXXX XXXXXXXXX XXXXXX XXXX ALGEBRA I
XXXXXXXX #1
(X) X(4x + X) is not an equation.
XXX other three options are XXXXXXXXX as XXXX are in XXX equation format.
XXXXXXXX #X
(a) XX cannot XXXXXXXXX XXXXXXX XX - 8 = 10 - x is true or XXXXX XX we XX not XXXX the value of XXX unknowns, and hence we do XXX XXXX if the equation XXXXX.
(b) If x = 5, XXX XXXXXXXX evaluates XX 10 - X = XX - 5 &XX;&XX;&XX; X = 5. XXX equation XXXX be XXXXX.
(c) XX - 8 = 10 - x
X(X) - X = XX - X
4 = X
span XXXXX="Apple-XXXXXXXXX-space"&XX;
XXXXXXXX #X
(a) XX + 3 = XX
2(X) + 3 = 17
17 = XX
XXX XXXXXXXX is true.
(b) (x - 20) = -4
X
(XX - XX) = -4
X
(-10) = -4
5
-X = -X
The XXXXXXXX is false
(c) X (x+X) = 6 (x - 1)
X (4 + 5) = 6 ( 4 - 1)
18 = XX
XXX XXXXXXXX is true
(d)
x2 -X = 2x + X
(-X)X -X = 2(-X) + 2
X -X = 2 - X
0 = X
The XXXXXXXX is true
(e) X (x + 2) - X = 5
4
3 ((X) + X) - 1 = 5
4
12 - X = XX
8 = XX
XXX equation XX false
(f) X/X x - X = -1/X x + 9
X/X (8) - X = -1/X (8) + X
6 - X = X - X
5 = X
The equation XX true
XXXXXXXX #X
XX - 3 = X x + 11
4(X) - 3 = X(7) + 11
XX = XX
It is correct as a XXXXXXXX.
XXXX’s XXXXX was to complete XXX XXXXXXXXXX X-X XXX X + 11 before XXX operations 4(X) and 2(X).
XXXXXXXXXXXXXX should always come before addition XXX XXXXXXXXXXX.
XXXXXXX
1. (a) Expression (b) Equation (c) XXXXXXXX (d) Expression (e) Expression (f) XXXXXXXX
2. (a) x - 4 = XX
X - 4 = 12
X = 12
(b) (X+x) / X = 3
(X+X) / 4 = X
XX/4 = X
XXX equation is XXXX. The solution is valid for the given equation.
(c) (x + X) - X(x-4) = X
(X + 2) - 3(4-4) = X
6 - 3(X) = 6
6 = X
XXX equation XX XXXX. XXX solution is XXXXX XXX XXX XXXXX XXXXXXXX.
(d) X/3 (x+X) = - 2/5 (x-9)
X/3 (X+X) = - 2/X (X-9)
2 = X
XXX XXXXXXXX is XXXX. The solution XX valid XXX the given equation.
Applications
3.
XXX 1: X = X(X) + X = 11
XXX 2: P = X(X) + 5 = XX
Day 3: P = X(3) + X = XX
XXX 4: P = 6(4) + 5 = 29
Day 5: P = X(X) + 5 = XX
Day X: X = 6(X) + 5 = XX
XXX X: X = X(7) + 5 = XX
Day 8: P = X(8) + 5 = 53
We will XXXXXXX XXXXX 1 on XXX X, XXXXX X on XXX 2 to X, Stage X XXX XXX X XX X, and incurable XXXXX on Day 8.
XXXXXXXXX
X. 25w + XX = 250
(a) XXXXXXX XXXXX 9 weeks = 25 (9) + 30 = 255
Yes, bobby will have enough as 255 > 250
(b) XXX + 30 + XXX = 250 + XXX
XXXXX 9 XXXXX XX saving = 25(X) + 30 + 10(9) = 345
XXXXX needs 250 + XXX = XXX
Nine XXXXX XX XXX enough XXXX for XXXXX to XXXX XX XXX < XXX
527CCAlg1U2L9SolvingLinearInequalities
SOLVING XXXXXX XXXXXXXXXXXX COMMON XXXX XXXXXXX I
Exercise #X
(a) XXX XXX inequality is X &XX; 11. XXXX is a true inequality.
(b) The new XXXXXXXXXX XX 0 < X. XXXX XX a true XXXXXXXXXX.
(c) The XXX XXXXXXXXXX XX X &XX; 16. This XX a XXXX XXXXXXXXXX.
(d) The new inequality XX X &XX; 4. XXXX is a XXXX inequality.
Exercise #2
(a) The new inequality is -8 &XX; -16. This is a XXXXX inequality.
(a) XXX new inequality is -2 &XX; -4. XXXX XX a XXXXX XXXXXXXXXX.
Exercise #X
(a) XXX inequality XX 5 < 8. When multiplied by -4, it XXXXXXX -20 &XX; -32. This becomes false.
Exercise #4
(a) 4x - 3 ≥ 5
4x ≥ 8
x ≥ X
(b) / (c)
XXX five XXXXXXX are X, 4, X, X, 7
XXX solution XX XXXXXXXXX XX XXX XXXXX >>>&XX;&XX;>&XX;>&XX;
>>&XX;&XX;>>>&XX;&XX;>&XX;>&XX;>&XX;&XX;>&XX;>>&XX;&XX;>>>>>&XX;>&XX;>&XX;
-XX -9 -8 -X -X -5 -4 -X -2 -X X X X 3 4 5 6 X 8 X 10
|XXXX|XXXX|____|____|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|XXXX|____|____|XXXX|____|XXXX|____|XXXX|XXXX|
Exercise #X
(a) Rewrite the left hand expression as an XXXXXXXXXX XXXXXXXXXX using addition.
8 - XX > 16
8 - XX &XX; XX
(b) XXXXX the XXXXXXXXXX
X - XX > XX
X - XX &XX; 2x
-X &XX; XX
-X &XX; x
x < -X
(c) Let x = -6
XX -X < -4, XXX XXXXXXXX XXXXXXXXXX XX true
(d)
The XXXXXXXX XX XXXXXXXXX XX the range &XX;&XX;&XX;>>>&XX;>&XX;
&XX;&XX;<<&XX;&XX;<&XX;<&XX;&XX;&XX;&XX;<<<<<&XX;&XX;&XX;&XX;<
-XX -X -X -7 -6 -X -4 -X -2 -1 X 1 2 X 4 X 6 7 X X 10
|XXXX|____|XXXX|____|XXXX|XXXX|XXXX|____|____|XXXX|XXXX|XXXX|____|____|XXXX|____|XXXX|XXXX|XXXX|XXXX|
XXXXXXXX #X
(a)
8 (x-2) - X (XX + X) ≤ XX + 4 - X(x+1)
XX - 16 - 6x - X ≤ 7x + X - XX - 3
XX - 19 ≤ XX + 1
-XX ≤ 20
(b)
8 (x-X) - 3 (XX + X) ≤ XX + X - 3(x+X)
XX - XX - XX - 3 ≤ XX + X - XX - 3
XX - XX ≤ XX + X
-2x ≤ 20
-x ≤ 10
x ≥ -10
O>&XX;&XX;>&XX;>>>>>>&XX;>>&XX;&XX;>>>>>&XX;>&XX;&XX;>>>&XX;&XX;
-16 -XX -14- 13 -12 -XX -XX -9 -X -7 -6 -5 -4 -X -2 -X 0
|____|XXXX|____|XXXX|XXXX|____|XXXX|XXXX|XXXX|____||____|____|XXXX|____|XXXX|XXXX|
XXXXXXX
(a)
5x - X ≤ 24
5x ≤ XX
x ≤ 6
XXX solution XX XXXXXXXXX XX XXX XXXXX >&XX;>&XX;&XX;>>&XX;&XX;
<&XX;<&XX;<&XX;&XX;<&XX;<<<<&XX;&XX;<<&XX;<&XX;&XX;<&XX;<&XX;<<<<&XX;&XX;<<&XX;<&XX;<&XX;&XX;&XX;&XX;<<<<&XX;&XX;&XX;&XX;<&XX;<&XX;<<<&XX;&XX;X
-10 -X -8 -X -6 -X -X -3 -X -X X X X 3 X 5 6 7 8 X XX
|____|XXXX|____|XXXX|XXXX|____|____|____|XXXX|XXXX|____|____|XXXX|____|____|____|____|XXXX|____|XXXX|
(b)
2(5-x) ≤ 12
XX - 2x ≤ XX
XX - 12 ≤ 2x
-2 ≤ 2x
-X ≤ x
XXX solution XX XXXXXXXXX by the XXXXX &XX;>&XX;&XX;&XX;&XX;>&XX;&XX;
&XX;<&XX;&XX;&XX;<<&XX;&XX;&XX;&XX;&XX;<&XX;&XX;<&XX;&XX;&XX;<&XX;<&XX;<<&XX;<&XX;<<&XX;&XX;<O
-XX -X -8 -7 -6 -5 -4 -X -X -X 0 X 2 3 X 5 6 7 8 X XX
|____|XXXX|____|XXXX|____|____|____|____|____|XXXX|XXXX|XXXX|____|XXXX|XXXX|XXXX|____|____|XXXX|____|
(c)
X - 4x > XX
-4x &XX; 12
x &XX; XX/-4
x &XX; -3
XXX XXXXXXXX is indicated by the XXXXX &XX;&XX;&XX;>>&XX;>&XX;&XX;
<<&XX;&XX;<<&XX;&XX;<&XX;<<&XX;&XX;<&XX;<&XX;&XX;<<&XX;&XX;&XX;&XX;<&XX;
-10 -9 -X -7 -X -X -4 -X -X -1 0 1 2 X 4 5 X 7 X X 10
|XXXX|____|____|XXXX|____|____|XXXX|____|____|XXXX|____|XXXX|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|____|
(d)
XX - X(x-2) > XX - 2x
8x - XX + 12 > 20 - 2x
XX + XX > XX - 2x
XX > XX - XX
XX > X
x &XX; X
>&XX;&XX;>&XX;&XX;&XX;>&XX;>&XX;>>&XX;&XX;>&XX;>&XX;>>>&XX;&XX;>&XX;
-10 -X -8 -7 -6 -5 -X -3 -X -X 0 1 2 3 X X X 7 X X XX
|XXXX|XXXX|XXXX|____|XXXX|XXXX|XXXX|____|XXXX|____|XXXX|XXXX|____|____|____|XXXX|XXXX|XXXX|____|____|
(e)
X (XX + X) > X x + X
6 X
X (XX + 2) &XX; 2x + 12
XX + X &XX; XX + 12
4x &XX; 6
x &XX; X.5
>&XX;>&XX;&XX;&XX;>>>>>&XX;&XX;>>&XX;>&XX;>&XX;&XX;&XX;&XX;&XX;>>>
-10 -9 -X -7 -6 -X -X -X -2 -1 X 1 X X 4 X X X 8 9 XX
|XXXX|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|____|XXXX|XXXX|____|XXXX|XXXX|____|____|XXXX|____|XXXX|XXXX|
XXXXXXXXXXXX
2. (a)
Edwin will XXX 45 + X.25n
Edwin will pay more than XXXX if:
45 + X.25n &XX; XXX
XXXXXXX the inequality:
5.25n > XXX - XX
5.25n &XX; XX
n > 12
(b)
Edwin can XXXX 11 XXXXX and still pay XXXX than XXXX. This XX XXXXXXX 12 XXXX make XXXX XXXXX, and 13 or XXXXX will XXXX XXXXX XX XXX more than XXXX.
XXXXXXXXX
3. (a) XX + b ≥ XX
ax ≥ XX - b
x ≥ (cd - b) / a
(b)
a (x + 2) &XX; c
b
ax + XX > bc
x > bc - XX
a
X. The XXXXXXX XXXXXX is (X)
ax + b > d
x &XX; (d - b) /a
≥ ≤
97150
XXXXXXXX 4: XXXXXX Day XXXXXXXXXXXXXXX/Dictatorship: A XXXXX of North Korea
What historical XXXXXXX XXX you provide XX XXX XXXXX XXXXXX Government XXXX XX associated with XXX enduring issue you XXXXX?
span class="XXXXX-converted-space">
XXXXX XXXXX XXX XXXXXX out of the repressive government of Kim Il-Sung, a post-XXX nationalist communist XXX XXXXXXXXX the XXXXX XXXXXXXXX of XXX XXXXX XXXXXX people in order XX deal XXXX XXXXXXXX emergencies XXXX as the Korean XXX. XXXXXXXXXXX, XXX Il-XXXX and XXX descendants have continued XX XXXXXXXXXXX power in a XXX XXXX curtails human XXXXXX in XXXXX XXXXX. They have XXXXXXX a regime XXXXX XXXX speech is disallowed, and where judicial penalties routinely XXXXX human XXXXXX. XXXXX XXXXXXX the use of torture, XXXXXX labor XXX XXXXXXXXXXXXX in XXXXXXXX XXXXXXXXXX. There is also XX XXXXXXXXXXX XXX process XXXXXX XXX judicial system. XXX lack XX human XXXXXX in XXXXX Korea XX a result XX decades XX XXXXXXXXXXXXX by the North Korean communist XXXXXXXXXXXX, in a bid to continue their firm grip on power over the XXXXXXX.
XXX XXXX XXX issue of power/human rights in XXX government of North XXXXX XXXXXX XXXXXX?
span XXXXX="XXXXX-converted-space"&XX;
94233
Regular equations
XX. x - 7 = X
x = X + X
x = XX
1b. x - b = a
x = a + b
2a. 4x = -12
x = -X
XX. -XX = m
k = m/(-X)
X = -X m
3
XX. XX - 5 = 11
x = (XX + 5)/X = 8
XX. 2b - 9 = d
b = (d + X) / X
XX. 1/X (4x) = -XX
XX = -40
x = -XX
XX. XXX = 10
g = 10 / XX
XX. x / -8 = 11
x = - XX
XX. y/3 = h
y = 3h
XXXXX
Document 4: Modern XXX Totalitarianism/XXXXXXXXXXXX: A Study of XXXXX XXXXX
XXXX XXXXXXXXXX context XXX you XXXXXXX XX the XXXXX Korean Government XXXX is associated with XXX enduring XXXXX you XXXXX?
span class="Apple-XXXXXXXXX-space">
XXXXX XXXXX was XXXXXX out XX XXX XXXXXXXXXX XXXXXXXXXX XX Kim XX-XXXX, a post-XXX XXXXXXXXXXX XXXXXXXXX who XXXXXXXXX XXX civil liberties XX XXX North Korean XXXXXX in order XX XXXX with XXXXXXXX emergencies such as the XXXXXX XXX. Furthermore, Kim Il-Sung and XXX XXXXXXXXXXX XXXX continued XX consolidate XXXXX in a way that XXXXXXXX XXXXX rights in XXXXX XXXXX. XXXX have created a regime XXXXX XXXX XXXXXX is XXXXXXXXXX, XXX where XXXXXXXX XXXXXXXXX XXXXXXXXX XXXXX XXXXX rights. XXXXX XXXXXXX XXX XXX of XXXXXXX, XXXXXX labor XXX XXXXXXXXXXXXX in XXXXXXXX XXXXXXXXXX. XXXXX is also no XXXXXXXXXXX XXX process within the XXXXXXXX XXXXXX. The XXXX of XXXXX XXXXXX in XXXXX Korea is a result XX decades of XXXXXXXXXXXXX by the XXXXX Korean communist XXXXXXXXXXXX, in a XXX XX continue their XXXX grip XX power over the XXXXXXX.
XXX XXXX the XXXXX of power/human XXXXXX in the XXXXXXXXXX XX North XXXXX XXXXXX people?
span XXXXX="XXXXX-XXXXXXXXX-XXXXX"&XX;
84417
Unit 2 Exam
X. X.
X. X.
9. X.
XX. 4.
76432
Literal XXXXXXXXX: Worksheet #1
6a.
XX = XX + XX
2x = 26 - XX
x = 12 / 2
x = 6
6b. XX = 7v + 5
7v = XX - X
v = (3d - X) /7
XX. -30 = X - 8x
8x = X + XX
x = XX/X
XX. 7a = XX - 2h
2h = 10 - XX
h = (10 - XX) /2
XX. X(x-X) = 12
3x - 12 = 12
XX = 24
x = X
8b. X(XX + p) = w
XXX + XX = w
5p = w - 20x
p = (w - XXX) / 5
Which XX equivalent XX XX - 8b = 10x
a = (10x + 8b) / 7
The XXXXXX is B
Which is XXXXXXXXXX to 4ab + X = XX
X = XX - 4ab
XXX XXXXXX XX C