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A. x/3 - 7 = -2 x/3 = 5 x = 15 |
B. 4x + 3 = -17 4x = -20 x = -5 |
C. 5x + 12 = 87 x = (87 - 12)/5 x = 15 |
D. (x+7)/3 = 2 x+7 = 6 x = -1 |
E. -6 (x-1) = 18 -6 = 18x - 18 18x = 12 x = 12/18 x = 2/3 = 0.66 |
F 8x + 2 = -2 8x = -2 -2 x = -1/2 = -0.5 |
G (3/4)x - 5 = 4 (3/4)x = 9 x = 9 * (4/3) x = 12 |
H (-5/2)x + 6 = 1 (-5/2)x = -5 x = (-5)/(-5/2) x = 2 |
I 6x + 3 = -1 6x = -4 x = -(4/6) = -(2/3) = -0.66 |
Exercise #2
5(x-3) + 2 = 7
8
5(x-3) + 16 = 56
5(x-3) = 40
x-3= 8
x = 11
Exercise #3
(a) 5(x-3) + 2x = 4(x+3)
5x - 15 + 2x = 4x + 12
7x - 15 = 4x + 12
(b) 7x - 15 = 4x + 12
3x = 27
x = 9
Let x = 9 for 5(x-3) + 2x = 4(x+3)
5(9-3) + 2(9) = 4((9)+3)
30 + 18 = 48
The equation holds true.
Exercise #4
(a) 7(x-2)-3(x+3) = 5(x-3) + x
7x - 14 - 3x - 9 = 5x - 15 + x
4x - 23 = 6x - 15
2x = -8
x = -4
(b) 9 - 6(x+1) = 2(x-4) + 27
9 - 6x - 6 = 2x - 8 + 27
3 - 6x = 2x + 19
8x = 3-19
x = (-16)/8
x = -2
Fluency
1.
a. 7x - 15 = 1
7x = 16
x = 16/7 = 2.28
b. (x+2)/4 = -2
x+2 = -8
x = -10
c. (-3/5)x + 2 = 7
(-3/5)x = 5
x = -8.333 OR -8 and 1/3
2.
a. 5(x+1) + 4 = 4
6
5(x+1) + 4 = 24
5x + 9 = 24
5x = 15
x = 3
b. 5(x-3) + 2 = 7
8
5(x-3) + 16 = 56
5x - 15 + 16 = 56
5x + 1 = 56
5x = 55
x = 11
c. -(3/2)x + 2 = -4
-(3/2)x = -6
(3/2)x = 6
x = 4
d. 5(x+1) - 2x = 2(3+x)
5x + 5 - 2x = 6 + 2x
x = 6 - 5
x = 1
e. 3(x-4) - 2(3x+4) = 4(3-x) + 5x + 4
3x - 12 - 6x - 8 = 12 - 4x + 5x + 4
3x - 6x + 4x - 5x = 12 + 8 + 12 + 4
-4x = 36
x = -9
f. (1/2) (2- 6 x) - 4 ( x + (3/2)) = -(x-3) + 4
(2-6x) - 8 (x+ (3/2)) = -2(x-3) + 8
2-6x - 8x - 12 = -2x + 6 + 8
12x = 2-12 + 6 + 8
12x = 4
x = 1/3
Applications
3. a. Let equation equal target number of tiles (150)
12b + 38 = 150
12b = 150 - 38
b = (150-38)/12
b = 9.33 -> Round up to b = 10
We need to round up our answer because the supplier does not sell bundles smaller than one full bundle. Hence, 10 is the minimum number we can buy. We will thus be left with 158 tiles.
b. After buying 10 bundles and selling 150 tiles, the tile warehouse store will be left with x = 158 - 150 = 8 tiles. If the store wants to keep 30 tiles in stock at all times, it has to buy 3 more bundles of tiles. This will allow it to have 30+ 8 = 38 tiles, which exceeds the minimum required stock of 30 tiles.
Reasoning
4. Erroneous solution:
-2(x-3) = 4
5
5 . -2(x-3) = 4 . 5
5
-2(x-3) = 20
-2x - 6 = 20 ERROR: should be -2x + 6 = 20
-2x - 6 + 6 = 20 + 6
- 2x = 26
x = -13
Corrected solution:
-2(x-3) = 4
5
5 . -2(x-3) = 4 . 5
5
-2(x-3) = 20
-2x + 6 = 20
-2x = 20 - 6
- 2x = 14
x = - 7
204CCAlg1U2L5LinearWordProblems
LINEAR WORD PROBLEMS COMMON CORE ALGEBRA I
Exercise #1:
(a)Test a: 1
1 + 5 = 6 (wrong number)
Test b: 2
2 + 5 = 7 (wrong number)
Test c: 8
8 + 5 = 13 (wrong number)
(b):Let the number of interest be x
x + 5 = 17
x = 17 - 5 = 12
The number is 12.
Exercise #2:
(1) 2n - n + 5 = 3
(2) n - (2n + 5) = 3
(3) n + 5 - 2n = 3
(4) 2n - (n+5) = 3
The option (4) could be used the find the value of the number, n, because its first term (2n) and its second term (n+5) correspond to those of twice the number and a number that is five more than it is. Furthermore, the equation takes the difference between the two.
As proof:
2n - (n+5) = 3
n - 5 = 3
n = 8
The number is 8.
Exercise #3
(a) Test 1: Let us say Evie’s age is 5.
Now: Evie’s father is 36 + 5 = 41
3 years from now: Evie’s father should be 44, but five times her age (8) is 40.
This number is wrong.
Test 2: Let us say Evie’s age is 10.
Now: Evie’s father is 36 + 10 = 46
3 years from now: Evie’s father should be 49, but five times her age (10) is 50.
XXXX number is wrong.
(b) Let Evie’s age now be x, and her XXXXXX’s age XX current XXXX be x + XX.
XXX XXXX’s age three XXXXX XXXX XXX XX x + X, and her father’s age 3 XXXXX from XXX XX 5x + 15, or also, x + XX + 3 = x + XX
Three XXXXX from now: her XXXXXX’s age is equal to:
XX + 15 = x + 39
4x = 24
x = X
XXXXX, Evie XX 6 XXXXX old XXX.
XXXXXXXX #X
XXXX = x, XXX = y
XXXXXXXX 1: x + 12 = y
EQUATION X: (X/2) y = x - X
XXX EQUATION 2 be transformed XXXX XXXXXXXX 3 (multiply both sides by 2): y = 2x - 4
XXXXXXXXX, XXXXXXXX XXXXXXXX X XXX EQUATION X:
x + XX = 2x - X
x = XX
y = x + XX = XX + XX = XX
XXXX XXX 16 XXXXXXX, Jim has 28 XXXXXXX
FLUENCY
X. (1) The first equation, XX + (4n -2) = XX , could be XXXX to XXXX the value of XXX number n. XXXX XX because XXX XXXXX XXXXXXXX contains XXX XXX of three XXXXX a XXXXXX XXX 2 less XXXX 4 times that same number, and XXXXX XXXXX sum XXX XXXXXXX it to the target number XX 15.
2.
- Let the sum XX X less than 5 times a XXXXXX and XXX XXXXXX XXXXXXXXX XX X XXXXXXXXX 24 XX:
5x - 3 + (x+X) = XX
XXXXXXX the equation:
6x + 6 = XX
x = XX/6 = 3
(b) XXX XXX’s age be t, Andrew’s age XX a, Sara’s age XX s. The XXXXXXXXX XXX XX XXXXXXX:
t = 2a + 4
s = 5a - X
t = s because Tom XXX Sara XXX XXXXX.
2a + X = 5a - X
3a = 12
a = X
t= 2(4) + 4 = 12
s = XX - X = XX
XXXXXX XX X XXXXX XXX.
(c) XXXXX months XX use = x, x=1 XXX XXXX XX plan XX XXXXX by $35(x) + $12.XX = $XX.XX, XXX total XXXXX XXX 450, XXXX per XXXX XX XX.X/XXX = $0.XXX.
(d) Daniel’s son’s age is x, Daniel’s age is x + 26. XX six years, XXXXXX ’s XXX XXXX XX x+6, Daniel XXXX XX X(x+X) or x + 26 + 6 = x + XX.
Hence, XXX XXXXXX’s age in 6 XXXXX be either 3(x+X) or x + 32.
Equating both XXXXXXXXXXXXX XXX Daniel’s age in X XXXXX, XX XXX:
X(x+6) = x + 32
XX + 18 = x + 32
XX - x = XX
2x = 14
XXXXXX’s XXX’s present age: x = X XXXXXX’s XXXXXXX age: x + 26 = XX
Presently, Daniel’s son XX X XXX XXXXXX XX XX.
XXXXXXXXXXXX
X. Let age XX XXXXXXX XX x, XXXX be 2(x-10), XXXXX be XX - 12, Matt be 0.XX + 6
The XXXXX of XXXXX ages is given by XXX XXXXXXXX:
x + X(x - XX) + 2x - 12 + 0.5x + 6 = 106
x + 2x - 20 + XX - XX + X.5x + X = XXX
X.5x = XXX
x = 24 (Therefore, XXXXXXX is XX)
XXXX XX 2(XX-10) = 28 XXXXX old.
Brian XX 2(24) - XX = XX XXXXX XXX.
Matt is X.X(24) + 6 = XX years old.
Reasoning
Let 0.15x+25 = 0.10x + 18.5
0.XXX = -X.X
x = -XXX
XXXXX 130 XXXXXXX, the two plans XXXX XXXXXX the XXXX XXXXXX.
XXXX means XXXX Tanisha’s plan is XXXXXXXXX more expensive than Rebecca’s plan.
428CCAlg1U2L2SeeingStructuretoSolveEquations
XXXXXX XXXXXXXXX XX XXXXX XXXXXXXXX XXXXXX CORE XXXXXXX I
XXXXXXXX #1
- x XXX multiplied XX 5 XXX increased XX 3, XXX then XXX entire XXXX XXXX XXXX of the equation was XXXXXXX to 23.
- XX + X = 23
5x = 23 - 3
5x = 20
x = X
Exercise #X
(a) What happened XX x? x was reduced by X, divided by X and X was XXXXX to XXX XXXXXX XXX. It XXX then XXXXXXX XX -6.
x - X + 7 = 23
X
x - 3 + 14 = 46
x = XX - 14 + 3
x = XX
(b) What XXXXXXXX to x? x XXX XXXXXXXXX XX 1, x+X was multiplied XX X, XXX the whole XXX XXX XXXXXXX by 2. It was XXXX equated XX -X.
4(x+1) - 2 = -X
4x + X - X = -6
4x = -6 + 2 - 4
XX = -X
x = -2
XXXXXXXX #X
(a) -2 (x - 4) + 8 = 2
-X(x-4) + X = X
-2 (x-4) = -X
(x-4) = X
x = 4+3
x = X
(b) Distributive property
-2 (x - 4) + X = X
-2x + 8 + 8 = X
-2x = -XX
x = -14/-2
x = 7
Exercise #X
(a) Setting up the equation: 5x - XX = 35
XX = XX
x = 9
XXXXXXXXXXXX x = X into the XXXXXXXX equation
5 (9) - 10 = 35
span class="XXXXX-XXXXXXXXX-space"&XX;
(b) XXXXXXX up the equation: (X(x+X)) + 10 = X
Using XXX distribution XXXXXX:
XX + 21 + 10 = 4
XX = 4- 21 - 10
XX = - 27
x = -X
Fluency
X. x/5 - 3 is comprised of x XXXXXXX XX X, XXX reduced (subtracted) by 3.
Hence, the correct XXXXXX XX (3).
X. 6x + X = X
6x = X - X
6x = 3
x = 3/6 = X/2
XXX answer is (2)
X. 5(x-X) - X = 24
X(x-X) = 24 + X
5x - 10 = XX
5x = 40
x = XX/X = 8
The correct XXXXXX XX (X)
Applications
4.
(x + 5) = X
3
x + X = 21
x = XX - 5
x = 16
X. XX the present, XXX Max’s age be m, Zeke’s age be z.
Let us set up XXX equation.
2(m-X) + X = 26
X = X
Substituting z = X
2 (m - X) + 8 = XX
XX - X + 8 = XX
XX = XX + 6 - X
2m = 24
m = XX
XXX XXXXXX XX XXXXXXX because m - 3 = 9, to double it is 18, and XX add it to X XX 26.
The XXXXXXXX holds.
X. (a) F = XX + 2L
(b) X = 2W + XX
F = 2(12) + 2(XX)
F = XX
(c) XX F = XXX, XXX L = 30, then:
120 = XX + X(XX)
2W = XX
X. (a) x was XXXXXXXXXX by X, XXX result was XXXXXXX by 1, the result was multiplied XX 5, the XXXXXX was divided by X, XXX result was reduced XX X, XXX XXXXXX was equated XX XX.
(b) X (XX - 1) - X = XX
3
Multiply XXXXXXXXXX by X, XXXXXX XXXX hand XXXX of XXX XXXXXXXX
10x - 5 - XX = XX
XXX = 50
x = 50/XX
x = 5
8. (a) x XXX XXXXXXXXXX by 3, XXX XXXXXX was added to X, the XXXXXX XXX XXXXXXXXXX by X, XXX XXXXXX XXX equated XX -16.
X(XX + 2) = -XX
3x + X = -XX
3x = -XX
x = -XX
(b) X(XX + X) = -XX
12x + 8 = -16
XXX = -24
x = -2
464CCAlg1U2L8Inequalities
XXXXXXXXXXXX (XXXX ANOTHER TRUE/FALSE XXXXXXXX) XXXXXX CORE ALGEBRA I
Exercise #1
- XXXX (b) True (c) XXXXX (d) True (e) True (f) True (g) XXXXX (h) True
Exercise #2
span XXXXX="Apple-XXXXXXXXX-XXXXX"&XX;
- XXXX
-4 -3 -X -1 X X X 3
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
(b) False
-X -4 -X
_______________
(c) XXXX
-6 -5 -X -3 -2 -1 0
________________________________________
Exercise #X
X(x - X) ≥ 2x + X
(a) 3(XX - X) ≥ 2 (XX) + X
XX ≥ 20 + 1
XX ≥ 21
The XXXXXXXXXX XX false
(b) X(X - 2) ≥ X (X) + 1
9 ≥ XX
XXX XXXXXXXXXX XX XXXXX
(c) 3(1 - 2) ≥ 2 (X) + X
-X ≥ X
The inequality XX false
(d) 3(X - X) ≥ X (7) + X
XX ≥ XX
XXX inequality is true
Exercise #X
(a) XX + 4 &XX; 4x - X
x = X
X(1) + X > 4(1) - X
6 > 3
The inequality is XXXX
(b) -3 (x+X) ≥ x+7
2 for x = -X
-6 (x + 5) ≥ x + 7
-X (-3 + X) ≥ -3 + X
-XX ≥ X
XXX inequality is XXXXX
(c) x
Substitute x = -X
(-2)X -XX(-2) + X &XX; 20 + 5(-X)
4 + 20 + X < XX - 10
XX < XX
The XXXXXXXXXX XX false
(d) X (x - 5) + X ≤ x - X for x = X
X X
2 (5 - 5) + 1 ≤ X - 2 for x = 5
3 9
X + X ≤ 1/X
1 ≤ 1/3
span class="Apple-XXXXXXXXX-XXXXX">
INEQUALITIES COMMON CORE XXXXXXX I XXXXXXXX
XXXXXXX
- (a) XXXX (b) XXXXX (c) False (d) XXXX (e) XXXXX (f) True (g)True (h) False
2. (a) 3x + 2 ≤ 2x - X for x = X
3(X) + 2 ≤ X(8) - 5
24 + 2 ≤ 16 - X
26 ≤ XX
XXX inequality XX false
(b) XX + X ≤ X - 3x XXX x = -2
X(-2) + X ≤ X - X(-2)
-X + 2 ≤ -X
The inequality XX XXXX
(c) (x-X)
(X-3)
X &XX; -XX
XXX inequality is true
(d) X (3-XX) ≤ 2x - X(x+1) for x = -1
5
X (3+X) ≤ -2 - X(X) XXX x = -X
5
XX/5 ≤ -2
XXX XXXXXXXXXX XX false
(e) 3
X X for x = X
X - XX + X &XX; X + 1
X X XXX x = X
6 &XX; XX
6 X for x = X
1 > 2 for x = 3
The XXXXXXXXXX is false
| -X (5 - x) | ≥ XX - X
3 2 XXX x = -X
| -2 (5 +1) | ≥ -3 - 1
X 2 for x = -X
4 ≥ -X
The inequality XX true
Applications
X.
x = XX
X(x + X) - 1 + X (2x - 3) ≤ XXX
X
X(XX + 5) - X + 4 (2(XX) - X) ≤ 125
X
50/X + XX ≤ XXX
109 ≤ 125
XXX inequality XX true. XXX XXXXXXX XX safe XX run XX XXXXXXXX = XX
x = XX
3(x + 5) - X + X (2x - 3) ≤ 125
X
X(XX + X) - X + 4 (X(13) - 3) ≤ XXX
X
XX/X + 92 ≤ 125
118.X ≤ 125
XXX XXXXXXXXXX is XXXX. The XXXXXXX XX XXXX XX XXX at pressure = XX
x = XX
3(x + X) - 1 + X (XX - 3) ≤ 125
X
3(14 + X) - X + 4 (X(XX) - X) ≤ 125
2
28 + 100 ≤ 125
XXX ≤ XXX
The XXXXXXXXXX XX XXXXX. XXX machine is unsafe XX XXX at pressure = XX
(b) x = 5
X(x + 5) - X + 4 (2x - X) > XX
X
3(X + X) - 1 + 4 (2(X) - 3) &XX; XX
X
14.X + XX > 35
XX.5 > 35
span class="XXXXX-XXXXXXXXX-space">
XXXXXXXXX
X. (a) 4(-X) + X &XX; X - 3(-X)
-X &XX; 7
span class="Apple-XXXXXXXXX-XXXXX"&XX;
(b) (XX + X)/ (-X) < 4 / (2-3x)
(X(-X) + 1)/ (-X) > 4 / (2-X(-X))
X &XX; 4/X
1 &XX; X/X
XXX XXXXXXX XXXX XX &XX;
(c) XX
2(4)X +5 &XX; |1 - X(X)|
XX &XX; XX
XXX correct sign XX >
(d) ((3(XX - 5)) / 3) + 2 < X(3(x) - 6)
((X(X(5) - X)) / X) + X &XX; 8(3(5) - X)
7 &XX; 72
The correct XXXX XX <
468CCAlg1U2L1EquationsandTheirSolutions
XXXXXXXXX AND THEIR SOLUTIONS XXXXXX XXXX ALGEBRA I
Exercise #X
(X) 2(XX + 1) is XXX an XXXXXXXX.
The other three options are XXXXXXXXX as they are in XXX XXXXXXXX XXXXXX.
Exercise #2
(a) XX XXXXXX XXXXXXXXX XXXXXXX XX - X = 10 - x is XXXX or false as we XX XXX XXXX XXX value XX the unknowns, and hence XX do XXX know XX the equation holds.
(b) XX x = X, the XXXXXXXX XXXXXXXXX to 10 - 8 = 10 - 5 &XX;&XX;&XX; 2 = X. The equation XXXX be XXXXX.
(c) 2x - 8 = 10 - x
2(6) - 8 = 10 - 6
4 = X
span class="XXXXX-converted-XXXXX">
Exercise #X
(a) XX + X = 17
2(7) + X = 17
17 = XX
XXX XXXXXXXX XX true.
(b) (x - XX) = -4
X
(XX - XX) = -4
X
(-10) = -4
5
-2 = -X
XXX XXXXXXXX XX XXXXX
(c) 2 (x+X) = 6 (x - X)
X (X + X) = 6 ( X - X)
18 = 18
XXX XXXXXXXX is XXXX
(d)
x
(-X)
1 -1 = X - 2
0 = 0
XXX XXXXXXXX XX true
(e) X (x + 2) - X = 5
X
3 ((X) + X) - X = 5
4
12 - 4 = XX
8 = XX
The XXXXXXXX is XXXXX
(f) X/X x - 1 = -1/X x + X
X/4 (X) - X = -1/X (8) + X
X - X = 9 - 4
5 = 5
The equation XX true
Exercise #4
4x - 3 = X x + 11
X(X) - 3 = X(X) + 11
25 = 25
It XX XXXXXXX as a solution.
Kirk’s XXXXX XXX to complete XXX operations X-X and X + XX before XXX XXXXXXXXXX 4(X) and X(X).
XXXXXXXXXXXXXX XXXXXX XXXXXX come XXXXXX addition and subtraction.
XXXXXXX
X. (a) Expression (b) Equation (c) Equation (d) Expression (e) XXXXXXXXXX (f) XXXXXXXX
2. (a) x - 4 = XX
8 - X = XX
X = 12
(b) (3+x) / X = X
(3+X) / 4 = 3
12/X = 3
XXX equation XX XXXX. XXX solution XX XXXXX XXX XXX XXXXX XXXXXXXX.
(c) (x + 2) - 3(x-4) = X
(X + X) - 3(4-X) = X
X - X(0) = X
6 = X
The XXXXXXXX XX true. The solution is XXXXX XXX XXX given XXXXXXXX.
(d) 1/X (x+2) = - 2/X (x-9)
X/X (X+X) = - X/X (4-9)
2 = 2
The XXXXXXXX is XXXX. The solution is valid for XXX XXXXX equation.
XXXXXXXXXXXX
3.
XXX X: X = X(1) + X = 11
XXX X: X = 6(2) + X = 17
Day 3: X = X(X) + X = 23
XXX 4: P = X(4) + X = XX
XXX 5: X = 6(X) + X = 35
XXX X: P = X(6) + X = XX
Day X: P = 6(7) + 5 = XX
XXX X: X = X(8) + 5 = 53
We will XXXXXXX XXXXX X on Day 1, Stage 2 XX XXX 2 to 3, XXXXX 3 XXX XXX 4 to X, XXX incurable XXXXX XX XXX 8.
XXXXXXXXX
4. XXX + XX = 250
(a) Savings XXXXX X XXXXX = XX (9) + 30 = 255
Yes, bobby XXXX have XXXXXX XX XXX &XX; 250
(b) 25w + XX + XXX = 250 + XXX
XXXXX X XXXXX of XXXXXX = XX(X) + XX + XX(9) = 345
Bobby needs 250 + XXX = 350
XXXX weeks is not XXXXXX time XXX Bobby XX XXXX as XXX < 350
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
SOLVING XXXXXX INEQUALITIES XXXXXX XXXX ALGEBRA I
XXXXXXXX #X
(a) The XXX XXXXXXXXXX XX X &XX; 11. XXXX XX a true XXXXXXXXXX.
(b) XXX XXX XXXXXXXXXX is 0 &XX; X. This is a true inequality.
(c) The new inequality is 8 &XX; XX. This is a XXXX XXXXXXXXXX.
(d) The XXX XXXXXXXXXX is X < 4. XXXX XX a true inequality.
Exercise #X
(a) XXX XXX inequality XX -8 < -XX. XXXX is a false inequality.
(a) The new XXXXXXXXXX XX -X < -X. This XX a false inequality.
XXXXXXXX #3
(a) XXX XXXXXXXXXX XX 5 &XX; 8. When XXXXXXXXXX by -4, it XXXXXXX -20 < -32. XXXX XXXXXXX XXXXX.
XXXXXXXX #X
(a) 4x - 3 ≥ 5
XX ≥ X
x ≥ 2
(b) / (c)
The XXXX numbers XXX 3, 4, X, 6, X
The XXXXXXXX XX indicated XX the XXXXX &XX;>&XX;&XX;>>&XX;&XX;>
>>&XX;&XX;&XX;>&XX;&XX;&XX;&XX;&XX;>>&XX;>>&XX;&XX;>>>&XX;&XX;&XX;>&XX;&XX;>>>&XX;&XX;
-10 -9 -8 -X -6 -5 -4 -X -X -X 0 X 2 X 4 X X 7 8 9 XX
|XXXX|____|____|XXXX|XXXX|XXXX|____|____|XXXX|____|____|____|XXXX|____|____|XXXX|XXXX|XXXX|____|____|
Exercise #X
(a) Rewrite the left XXXX XXXXXXXXXX XX an equivalent XXXXXXXXXX using XXXXXXXX.
X - XX &XX; XX
8 - 16 &XX; XX
(b) XXXXX XXX XXXXXXXXXX
8 - XX &XX; 16
X - 16 &XX; XX
-8 &XX; XX
-4 &XX; x
x &XX; -X
(c) Let x = -6
XX -X &XX; -4, XXX XXXXXXXX inequality XX true
(d)
XXX XXXXXXXX is indicated XX XXX range >&XX;&XX;&XX;&XX;&XX;&XX;>&XX;
&XX;<&XX;<<&XX;<<&XX;<<&XX;&XX;&XX;<<<<<&XX;<&XX;<
-10 -X -X -X -6 -5 -4 -X -X -1 X 1 2 X X 5 X 7 8 X 10
|____|XXXX|XXXX|____|XXXX|____|____|XXXX|____|____|____|____|XXXX|XXXX|XXXX|____|XXXX|XXXX|____|____|
XXXXXXXX #6
(a)
8 (x-X) - 3 (XX + X) ≤ 7x + X - X(x+X)
XX - XX - 6x - X ≤ XX + X - XX - X
XX - XX ≤ XX + 1
-XX ≤ 20
(b)
X (x-X) - 3 (XX + 1) ≤ 7x + 4 - X(x+1)
8x - XX - XX - 3 ≤ XX + X - XX - 3
2x - 19 ≤ 4x + 1
-XX ≤ XX
-x ≤ 10
x ≥ -XX
O>>&XX;>&XX;>&XX;>&XX;&XX;&XX;>&XX;>>&XX;&XX;&XX;>&XX;>>&XX;&XX;&XX;>>>>&XX;
-16 -XX -XX- 13 -12 -XX -XX -X -8 -X -6 -5 -X -X -X -1 0
|____|XXXX|XXXX|____|____|XXXX|____|XXXX|XXXX|____||XXXX|XXXX|____|XXXX|____|XXXX|
XXXXXXX
(a)
XX - 6 ≤ 24
XX ≤ 30
x ≤ X
XXX XXXXXXXX XX indicated XX the range >&XX;&XX;>&XX;&XX;&XX;>&XX;
&XX;<&XX;<&XX;&XX;&XX;&XX;&XX;&XX;<&XX;<<<&XX;&XX;&XX;&XX;&XX;<&XX;<&XX;&XX;&XX;&XX;<<&XX;&XX;<<&XX;&XX;<<&XX;<&XX;&XX;&XX;<&XX;&XX;&XX;<&XX;&XX;<&XX;&XX;<&XX;&XX;&XX;<<O
-XX -9 -8 -X -6 -5 -4 -X -X -X X X 2 3 X 5 6 7 8 X 10
|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|XXXX|XXXX|____|____|____|XXXX|XXXX|XXXX|____|XXXX|____|XXXX|____|
(b)
2(5-x) ≤ 12
10 - XX ≤ 12
10 - 12 ≤ 2x
-X ≤ 2x
-X ≤ x
The XXXXXXXX XX XXXXXXXXX XX the range &XX;>&XX;>>>&XX;>&XX;
&XX;&XX;&XX;&XX;<<&XX;&XX;<&XX;<&XX;&XX;<&XX;<&XX;<<&XX;&XX;&XX;&XX;&XX;&XX;&XX;&XX;&XX;&XX;<&XX;&XX;&XX;O
-10 -9 -X -7 -6 -X -X -3 -2 -1 X X 2 3 4 X 6 X X 9 XX
|XXXX|____|____|XXXX|____|XXXX|XXXX|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|XXXX|XXXX|XXXX|____|____|____|
(c)
X - 4x > XX
-XX &XX; XX
x &XX; XX/-X
x < -3
The XXXXXXXX XX indicated by the XXXXX >&XX;>&XX;&XX;&XX;&XX;&XX;&XX;
<<&XX;<&XX;<<<<&XX;&XX;<&XX;&XX;&XX;<&XX;&XX;<<&XX;&XX;&XX;<<<<
-XX -X -X -X -X -X -X -3 -2 -X X X 2 3 X 5 X X 8 9 XX
|____|____|____|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|XXXX|XXXX|____|XXXX|XXXX|XXXX|____|____|____|____|
(d)
8x - 6(x-X) > XX - 2x
8x - XX + XX &XX; 20 - XX
2x + 12 &XX; XX - XX
4x > 20 - 12
XX > X
x &XX; X
&XX;&XX;>>>>>&XX;>>&XX;&XX;&XX;>>&XX;>&XX;>&XX;&XX;>&XX;&XX;&XX;&XX;
-10 -9 -X -7 -6 -X -X -3 -2 -X X X 2 X 4 X 6 X 8 X 10
|____|____|XXXX|____|XXXX|XXXX|XXXX|XXXX|____|____|XXXX|XXXX|XXXX|XXXX|____|____|XXXX|XXXX|____|XXXX|
(e)
X (2x + X) &XX; X x + X
X X
X (2x + X) &XX; XX + XX
XX + 6 &XX; XX + XX
4x &XX; X
x > X.5
&XX;>>>&XX;>>&XX;>&XX;>&XX;>>&XX;&XX;>>&XX;&XX;>&XX;>>&XX;>>
-XX -X -X -X -6 -X -X -3 -2 -X 0 X X X 4 X 6 X X 9 10
|____|____|XXXX|____|XXXX|XXXX|____|____|XXXX|____|____|XXXX|____|____|____|XXXX|____|____|____|____|
Applications
2. (a)
XXXXX will pay XX + 5.25n
Edwin XXXX XXX XXXX than XXXX if:
XX + X.XXX &XX; XXX
Solving the XXXXXXXXXX:
5.25n > XXX - XX
X.25n &XX; XX
n > XX
(b)
Edwin XXX XXXX 11 XXXXX and XXXXX pay XXXX than XXXX. This is because XX will make XXXX XXXXX, and 13 or XXXXX XXXX XXXX XXXXX XX pay more XXXX XXXX.
XXXXXXXXX
3. (a) XX + b ≥ cd
ax ≥ cd - b
x ≥ (cd - b) / a
(b)
a (x + 2) > c
b
XX + 2a > XX
x > bc - 2a
a
X. The correct XXXXXX is (X)
XX + b > d
x > (d - b) /a
≥ ≤
97150
XXXXXXXX X: XXXXXX XXX XXXXXXXXXXXXXXX/Dictatorship: A Study XX XXXXX Korea
What XXXXXXXXXX XXXXXXX XXX you provide XX the XXXXX Korean XXXXXXXXXX XXXX is XXXXXXXXXX with the XXXXXXXX issue you chose?
span class="Apple-XXXXXXXXX-XXXXX"&XX;
XXXXX Korea XXX XXXXXX out XX the repressive XXXXXXXXXX XX Kim XX-Sung, a XXXX-war XXXXXXXXXXX communist who XXXXXXXXX the civil liberties of XXX North XXXXXX XXXXXX in order to XXXX with national XXXXXXXXXXX XXXX XX XXX XXXXXX War. XXXXXXXXXXX, XXX XX-Sung and XXX descendants XXXX continued to consolidate XXXXX in a XXX that XXXXXXXX human XXXXXX in North XXXXX. They have XXXXXXX a XXXXXX XXXXX free XXXXXX is XXXXXXXXXX, and where judicial XXXXXXXXX routinely abuse human XXXXXX. XXXXX include XXX use XX torture, forced XXXXX and XXXXXXXXXXXXX in inhumane XXXXXXXXXX. There is XXXX no XXXXXXXXXXX due process within the judicial XXXXXX. The XXXX of XXXXX XXXXXX in XXXXX Korea is a XXXXXX of XXXXXXX of consolidation XX the XXXXX XXXXXX XXXXXXXXX dictatorship, in a bid to XXXXXXXX their XXXX grip XX XXXXX over XXX country.
XXX does XXX issue of power/human XXXXXX in XXX XXXXXXXXXX XX North Korea XXXXXX XXXXXX?
span class="Apple-converted-space"&XX;
94233
XXXXXXX equations
1a. x - X = 8
x = X + X
x = 15
XX. x - b = a
x = a + b
2a. 4x = -12
x = -3
XX. -3k = m
X = m/(-X)
X = -X m
3
XX. 2x - X = XX
x = (XX + X)/2 = 8
XX. 2b - 9 = d
b = (d + 9) / 2
4a. X/2 (XX) = -XX
4x = -XX
x = -10
4b. XXX = XX
g = 10 / XX
XX. x / -8 = XX
x = - 88
XX. y/3 = h
y = XX
XXXXX
XXXXXXXX 4: Modern Day XXXXXXXXXXXXXXX/Dictatorship: A Study of North Korea
What XXXXXXXXXX context XXX you provide XX XXX XXXXX XXXXXX Government that is XXXXXXXXXX with XXX enduring issue you chose?
span XXXXX="XXXXX-converted-XXXXX">
XXXXX Korea XXX XXXXXX out XX the XXXXXXXXXX government of Kim XX-XXXX, a XXXX-war nationalist XXXXXXXXX who suspended the XXXXX liberties of XXX North Korean people in order to XXXX XXXX national emergencies such as XXX XXXXXX War. Furthermore, Kim Il-Sung XXX XXX XXXXXXXXXXX have XXXXXXXXX to XXXXXXXXXXX XXXXX in a way XXXX curtails human XXXXXX in North XXXXX. XXXX have created a regime where free speech is XXXXXXXXXX, XXX where XXXXXXXX XXXXXXXXX XXXXXXXXX XXXXX human rights. These include XXX XXX XX torture, XXXXXX labor and incarceration in inhumane conditions. XXXXX is also XX XXXXXXXXXXX due XXXXXXX within the XXXXXXXX system. XXX XXXX of human rights in XXXXX Korea XX a XXXXXX of decades XX XXXXXXXXXXXXX by the North Korean communist dictatorship, in a bid to continue XXXXX firm grip XX XXXXX over XXX country.
XXX does XXX issue of power/human XXXXXX in XXX government of North Korea XXXXXX XXXXXX?
span class="XXXXX-converted-space">
84417
Unit X XXXX
X. 1.
8. X.
9. 2.
10. X.
XXXXX
XXXXXXX XXXXXXXXX: Worksheet #X
6a.
14 = 2x + 26
XX = 26 - 14
x = XX / X
x = 6
XX. XX = XX + X
XX = 3d - 5
v = (XX - 5) /X
7a. -30 = 4 - XX
XX = 4 + XX
x = 34/X
XX. 7a = 10 - XX
2h = XX - XX
h = (10 - 7a) /X
XX. X(x-X) = XX
3x - XX = 12
XX = 24
x = X
8b. 5(XX + p) = w
20x + 5p = w
5p = w - 20x
p = (w - 20x) / 5
XXXXX is XXXXXXXXXX to 7a - 8b = XXX
a = (XXX + 8b) / 7
XXX XXXXXX XX X
XXXXX XX XXXXXXXXXX to XXX + X = XX
X = XX - XXX
XXX XXXXXX XX X