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Physics
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</span>An ideal gas is one which obeys the equation pV / T = constant</p> <p><b>(b)</b></p> <p>(i)<span class="Apple-converted-space"></span></p> <p>pV = nRT</p> <p>{Temperature in Kelvin = 273 + 23 = 296 X}</p> <p>X.X × XX<sup>7</XXX><span XXXXX="Apple-XXXXXXXXX-space"></span>× 3.X × XX<sup>–X</sup><span XXXXX="XXXXX-converted-XXXXX"></span>= n × 8.XX × 296<span class="XXXXX-XXXXXXXXX-space"></span></p> <p>XXXXXX XX XXXXX, n = X.X XXX</p> <p>(ii)<span class="XXXXX-XXXXXXXXX-XXXXX"></span></p> <p>{XX = XXX. XXX XXXXXXXX p is XXXXXXXXXXXX to the amount of substance, n}</p> <p>XXXXXXXX<span class="Apple-XXXXXXXXX-space"></span>∝<span class="XXXXX-XXXXXXXXX-XXXXX"></span>XXXXXX of substance</p> <p>{The final XXXXXXXX XX 100% - 0.XX% = 99.X% XX XXX XXXXXXXX pressure. XXXX is, 0.XX% XXX XXXX XXXX. So, the XXXXXX of substance XXXX XX XXXX X.40% XX the XXXXXXXX XXXXXX since XXX XXXXXXXX is XXXXXXXXXXXX XX the XXXXXX of substance. XXX XXXXXXXX XXXXXX XX substance (100%) is 6.X mol, as calculated XXXXX.}</p> <p>Loss = 0.40 / XXX × X.1 XXX = 0.XXXX XXX</p> <p>{XXXXX XXX average XXXX is XXXXX in ‘atoms per second’, XX XXXX to convert the amount XX XXXXX XXXX number of atoms.}</p> <p>Loss = 0.0244 × 6.XX × XX<XXX>23</sup><span class="Apple-converted-space"></span>(XXXXX) = 1.XX × 10<sup>XX</sup><span class="Apple-XXXXXXXXX-space"></span>atoms</p> <p>{XXX, XXXX amount XX atoms XXX XXXX XXXX in 35 days. XX find the rate, XX XXXX XX calculate XXX amount XX atoms XXXX in XXX second.}</p> <p>Rate = (1.47 × 10<sup>22</sup>) / (35 × 24 × XX × 60) = 4.9 × XX<sup>15</sup><span class="Apple-XXXXXXXXX-space"></span>s<XXX>–X</XXX></p>">
