So, to XXXXXXXXX XXX XXXX of XXX above graph i.e. XXXXXXX it's an Euler XXXX or Euler circuit, we'll start with XXXX formation moving XXXX XXX XXXXX XXXX once and XXXXXXXXXXX XXXXXXX XXX starting and XXXXXX path XX XXXX or XXX.
XX'll take the XXXX in order as follows:
1(XXXXX) - X - 6- 3 - X - 7 - 11 - 10 - X - XX - 12 - 8 - 15 - XX - 13 - 19 - 21 - 22 - 20 - XX - XX - XX - XX - XX - 5 - 1 (XXX)
Since, the starting and XXXXXXXXX vertex are same, XXX graph XX an XXXXX circuit.
A XXXXX XXX XXXX attached XX XXXX illustrative XXXXXXXXXXX of XXX path formation of XXX question.
This method XXXXXXXXXXXXX, i.e., XXXXX a XXX of time. The XXXXXX is XXXX if we XXXX a complete graph, with N XXXXXXXX then XXXXX are (N-1)! XXXXXXXX XX list, calculate the weight, XXX then XXXXXX XXX XXXXXXXX XXXX. Even if we cut XXXX XXXX number XX (N-X)! by half, XXXXX XXX N as XXXXX XX 28, XXX time it XXXXX XXXX the fastest computers of our day XXBrute-Forceis XXXXXX than XXX age XX our XXXXXXXX.Thus, XX normally XXXXX XXXXX force method XXX graphs XXXXXX XXXXXXXX greater XXXX X.