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in a data set. The goal of each is to get an idea of a <strong>"typical"</strong> value in the data set. The mean is commonly used, but sometimes the median is preferred.</p> <p><strong>Range</strong> and <strong>interquartile range (IQR)</strong> both measure the<strong> "spread"</strong> in a data set. Looking at spread lets us see how much data varies. Range is a quick way to get an idea of spread. It takes longer to find the IQR, but it sometimes gives us more useful information about spread.<br></p> <p><br></p> <p><strong>XXXXX Data XXX (XXXXXX XX times stopped by the XXXXXX)!</strong><XX></p> <p><XXXXXX>X.</XXXXXX>XXX XXXXXXXXXX XXXX (average) is the sum XX the XXXXXX in XXX set XXXXXXX by the XXXXXX of XXXXXXXX in that set.</p> <p>XX the XXXXX data XXX, XXX sum of all the values XX XX. The XXXXXX of terms in XXX data set XX 20.</p> <p>XX XXX XXXX XX given XX:</p> <p>Mean = 81/XX</p> <p>= 4.XX</p> <p><XX></p> <p><strong>X.</strong>The median XX the value XXXXXXXXXX XXX XXXXXX half XX the XXXX set, XXXX XXX XXXXX XXXX.</p> <p>If the XXXXXX XX XXXXX is XXX, then XXX median XXX middle XXXXXXX of XXX XXXXXX set.</p> <p>XX XXX number of terms XX XXXX, XXXX the XXXXXX XX XXX arithmetic XXXX of the XXX middle XXXXXXXX of the XXXXXX set.</p> <p>By arranging the given data set in XXXXXXXXX order, we XXX:</p> <p>X, 0, 0, X, 1, 2, X, X, X, 4, X, X, X, 6, X, 7, X, X, 8, 10</p> <p>Since XXX number of XXXXX is even (20), the XXXXXX is XXX XXXXXXX of the two XXXXXX elements, 4 and X given XX:</p> <p>XXXXXX = 4+X/2 = 8/X</p> <p>= X</p> <p><br></p> <p>In XXX first XXXX XXX, <XXXXXX>median </XXXXXX>would be the most appropriate measure XX <strong>"central tendency"</strong>. Median XXXXXXXXXXXXX XXX XXXXXX XX XXXXX XXXXXXX by the police, because the<em>mean</em>XX a little XXX XXXXXX than XXXX XX all XXX values in XXX XXXX set.</p> <p><br></p> <p><strong>X. </XXXXXX>XXXXXXXX XXXXXXXXX XX XXXX as a measure XX dispersion when mean XX used as measure XX central XXXXXXXX (ie, XXX XXXXXXXXX XXXXXXXXX data). XXX ordinal XXXX or XXXXXX numerical XXXX, median XXX interquartile XXXXX are XXXX.</p> <p><br></p> <p><strong>XXXXX, XXXXXXXXXXXXX range is the difference of XXX XXXXX and XXXXX quartiles.XXX XXXXX quartile XX XXXXXXXX by XXXXXX XXX median XX the lower half XX a sorted set.The XXXXX quartile XX XXXXXXXX by taking XXX median XX XXX XXXXXX XXXX XX a XXXXXX XXX.</strong><XX></p> <p>XX XXXX:</p> <p>First XXXXXXXX = X.5 XXX XXXXX XXXXXXXX = 7<br></p> <p><XXXXXX>XX,XXXXXXXXXXXXX XXXXX = X - 1.X = 5.X</strong></p> <p><br></p> <p><XX></p> <p><XXXXXX>XXXXXX Data XXX (Religions)!</strong></p> <p>XXX XXXXX variable in the XXXXXX XXXX set XX XXXXXXXX. XXXX XXXXXXXX is a nominal XXXXXXXX. The appropriate XXXXXXX XX XXXXXXX XXXXXXXX XX XXXX XXX there is no XXXXXXX XX spread for XXXXXXX variable. Frequency XXXXXXXXXXXX for religion can XX found by recording XXX number XX XXXXX each religion XXXXXX in the XXXXX XXXX.</p> <p>Mode is the XXXX XXXX XXXXXXX frequency. Here '51' XX XXX highest XXXXXXXXX corresponds to the religion XXXXX. There XX XX XXXXXXX of spread XX XXXXXXXXXX XXX XXXX data. The XXXX XXXXXXXX that XXX XXXXXXXX of XXX respondents XXXXXXX XX XXXXX XXXXXXXX.</p> <p><strong>XXXXXXX XXXXXXXX ---> XXXX = 51</XXXXXX></p> <p></p> <p><strong><br></strong></p> <p><XXXXXX>Third Data Set (XXXXXX XX XXXXXX XXXXXXXX in XXX XXXX week)!</strong></p> <p></p> <p>In XXX lest XXXX set, most appropriate meausre of XXXXXXX XXXXXXXXX would XX "mean" and XXXXXXX of dispersion would be "standard XXXXXXXXX".</p> <p><br></p> <XXXXXX><XXX src="https://schoolsolver.s3.amazonaws.com/XXXXX/attachments/949Last.jpg" XXXX-s3="XXXXX://schoolsolver.XX.amazonaws.XXX/XXXXX/XXXXXXXXXXX/XXXXXXX.XXX"></XXXXXX> <p><XX></p> <figure><img src="https://XXXXXXXXXXXX.s3.XXXXXXXXX.XXX/XXXXX/attachments/XXXXXXXX.XXX" data-XX="https://schoolsolver.s3.XXXXXXXXX.XXX/XXXXX/attachments/XXXXXXXX.jpg"></figure> <p><XXXXXX><XX></XXXXXX></p> <p><XXXXXX>That's it!</strong></p>">
