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Parallelograms Quiz
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parallelogram <em>bisect</em></span>each other.<br></p><p>So AE = CE</p><p>x^2 - 8 =<strong></strong> 2x<br></p><p>x^2 - 2x - 8 = 0<br></p><p>(x-4)(x+2)=0</p><p>x = 4 or x=-2( invalid due to -ve sign)</p><p>AE = 2CE = 2*2x = 2*2*4 = <strong>16</strong></p><p><br></p><p>X. The XXXXXXXX XX the supplementary XXXXXX XX a parallelogram XX XXX°.</p><p>So ∠XXX + ∠XXX = XXX°</p><p>∠XXX =XXX°-∠ABC = 180° - XXX° = <strong>77°</XXXXXX></p><p></p><p>3. According XX XXX law of parallelogram, opposite<em> XXXXX</em> XXX equal,XXXXXXXX <em>angles</em> are XXXXX XXXXXX XXXXXXXXX <span class="center"><em>bisect</em></span>XXXX XXXXX; but there are <em>4 sets</em>XXXXXXXXXXXXX angles.</p><p>XX the <XXXXXX>1st XXXXXX XX wrong </strong>and XXXX XXX<XXXXXX> XXXXX XXXXXXX XXX Correct answer.</strong></p><p>X.</p><p><XXXXXX>XXXXXXXXX - Reason</XXXXXX></p><p>XXXXXXXXXXXXX - Given</p><p>KL II NM XXX KN II XX - Definition XX XXXXXXXXXXXXX</p><p>m∠X + m∠N =180° - XXXX-Side Interior angles XXXXXXX<br></p><p>m∠X + m∠M = XXX° - Same-Side XXXXXXXX XXXXXX Theorem</p><p>m∠X + m∠X=180° - Same-Side XXXXXXXX XXXXXX XXXXXXX<XX></p><p>m∠K+ m∠N =m∠X + m∠X - Transitive Property of XXXXXXXXXX</p><p>m∠X+ m∠X =m∠K + m∠X - Transitive Property of Congruence<XX></p><p>m∠N =m∠X - XXXXXXXXXXX Property XX XXXXXXXX<XX></p><p>m∠M =m∠K - Subtraction XXXXXXXX XX Equality<XX></p><p>∠N ≅∠L XXX ∠M ≅∠X - Angle Congruence XXXXXXXXX<br></p><p><br></p><p>X. </p><p>XXX XXXXXXXXXXX XX point X are ( <XXXXXX>a+b,</strong>c) .......................................... XX <XXXXXX>X</XXXXXX>( a+b, o+c) </p><p>The coordinates XX XXX XXXXXXXX of XXXXXXXX AC are (<XXXXXX>a+b/2</XXXXXX>, c/X) ,,,,,,,,,,, as ( X+a+b/2, X+c/X)<br></p><p>The coordinates of the XXXXXXXX XX diagonal XX are ( a+b/2, <XXXXXX>c/2</XXXXXX>) .............XX ( a+b/2, X+c/2)<XX></p><p>AC and BD XXXXXXXXX at point E with XXXXXXXXXXX( <strong>a+b/2</XXXXXX>,<b>c/X</b>) ..................midpoint XX both AC andBD at E</p>">
