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An officer states that the average fine levied b
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<p>Null Hypothesis: u<= 200.</p><p>Alternative Hypothesis: u>200</p><p>XX XXXXXX the XXXX XXXXXXXXXX XX XX true XXX XXX to either reject it or XXXX XX reject it.</p><p>XX XXXXXXX XXXX test, we need the standard deviation of XXX XXXXXX XXXXX XXXXX is XXXXX XX the XXXXXXX:</p><p>(XXXXXX XXXXXXXX XXXXXXXXX)/XXXX(sample XXXX) = XX/sqrt(10) = 5.XX</p><p>XXXX XX calculate the t-score: (sample mean - XXXXXXXXXX mean)/(XXXXXXXX deviation of XXXXXX mean) =</p><p>(210 - 200)/X.XX = X.XXX</p><p>XX need XX find XXX probability of obtaining a t-score of X.976 or XXXXXX, so we use XXXXXX a table XX p-XXXXXX XXX a t-distribution or a calculator's tcdf() function.</p><p>For XXXXXX XX these XXXXXXX, we XXXX the degrees of XXXXXXX XXXXX equals sample XXXX - X = 10 - X = X.</p><p>XXXXX a table, just XXXX XXX p-value for the t-XXXXX XXX degrees of freedom.</p><p>XXX a XXXXXXXXXX (such as Ti-XX), use XXXXXXXX tcdf(1.976, X*10^99,X) = X.0398 = p-XXXXX.</p><p>XXXXX the p-value, X.XXXX, XX XXXX XXXX XXX significance level XX X.XX, we can XXXXXX XXX XXXX. XXXXX XX significant XXXXXXXX XXXX the XXXXXXX XXXX is higher XXXX $200.</p><p>Note: XX XXXXXX XXXXXX a XXXXXXXXXX, only XXXXXX or fail XX XXXXXX. XXXX this XXXXX :)</p>">
