Speed of boat alone = 40 mph
Let speed of current= c
Let time= t
When boat travels with the current, the speed of the current pushes boat along therefore,
Total speed of boat= speed of boat alone + speed of XXXXXXX= ( 40+c )
XXXXXXX XXXX speed in XXXXXXXX (i),
(40+c) × t = XXX
XXXXXXXXXXX out the brackets
40t + ct= XXX (XX’ll call XXXX XXXXXXXX XX)
XXXX boat XXXXXXX against XXX XXXXXXX, the speed XX the current XXXXX XXXX XXXX XXXXXXXXX,
Total XXXXX XX boat= XXXXX of boat aloneXXXXX XX current= (40c)
XXXXX, putting this speed in XXXXXXXX (i),
(40c ) × t = 126
XXXXXXXXXXX out the XXXXXXXX
40t(we’ll call XXXX equation XXX)
XXXXXXXXX equations ii and iii
XXX + XX= XXX
XXX
Solving these as XXXXXXXXXXXX equations, we can XXX XXX XX XXX XXXX ‘XX’ by adding XXXX equations ii XXX iii. XXXX gives:
XXX + XX= 126
+ 40t
XXX = XXX
t=
t=3 hours
Substitute or put ‘t=X hours’ in equation XX
(40+c)
120+ 3c= 126
XX= 126-120
XX= 6
C=
C=X XXX
XXXXX of current= 2mph