Speed of boat alone = 40 mph
Let speed of current= c
Let time= t
When boat travels with the current, the speed of the current pushes boat along therefore,
Total speed of boat= speed of boat alone + spXXX XX XXXXXXX= ( XX+c )
Putting XXXX XXXXX in equation (i),
(40+c) × t = XXX
Multiplying out XXX XXXXXXXX
40t + XX= 126 (we’ll XXXX this XXXXXXXX XX)
When XXXX XXXXXXX against the current, XXX XXXXX XX XXX current XXXXX boat back XXXXXXXXX,
XXXXX speed of XXXX= speed of boat alonespeed of current= (XXc)
XXXXX, putting this speed in XXXXXXXX (i),
(40c ) × t = 126
XXXXXXXXXXX out the brackets
XXX(XX’ll XXXX XXXX XXXXXXXX XXX)
Comparing equations ii and XXX
40t + ct= XXX
40t
Solving XXXXX XX simultaneous XXXXXXXXX, XX XXX XXX rid XX XXX term ‘ct’ by adding both XXXXXXXXX ii and iii. XXXX XXXXX:
40t + ct= 126
+ 40t
80t = 240
t=
t=3 hours
Substitute or put ‘t=3 hours’ in equation ii
(40+c)
120+ 3c= XXX
3c= 126-XXX
3c= 6
C=
C=X mph
XXXXX of current= 2mph