Speed of boat alone = 40 mph
Let speed of current= c
Let time= t
When boat travels with the current, the speed of the current pushes boat along therefore,
Total speed of boat= speed of boat alone + spXXX of XXXXXXX= ( XX+c )
Putting XXXX XXXXX in equation (i),
(40+c) × t = XXX
Multiplying out XXX XXXXXXXX
XXX + XX= XXX (XX’ll call this XXXXXXXX ii)
XXXX XXXX travels against XXX XXXXXXX, the speed XX XXX current pulls boat back therefore,
Total speed XX XXXX= XXXXX XX boat XXXXXspeed XX current= (XXc)
Again, putting this XXXXX in XXXXXXXX (i),
(XXc ) × t = XXX
XXXXXXXXXXX out the brackets
XXX(XX’ll XXXX this equation iii)
Comparing XXXXXXXXX XX XXX iii
XXX + XX= 126
XXX
Solving XXXXX as simultaneous equations, XX XXX XXX XXX of the XXXX ‘ct’ XX adding both equations XX and iii. This XXXXX:
40t + ct= XXX
+ XXX
80t = XXX
t=
t=X XXXXX
XXXXXXXXXX or put ‘t=X hours’ in equation ii
(XX+c)
120+ 3c= 126
XX= 126-XXX
XX= 6
X=
C=2 mph
Speed XX XXXXXXX= XXXX